topic Re: statement not valid or used out of proper order in SAS/IML Software and Matrix Computations

statement not valid or used out of proper order

desireatem — Wed, 06 Nov 2013 23:46:24 GMT

NOTE: Line generated by the invoked macro "SURV".

26 (InverseC^=0))]; print t; tt=t(t); *print tt;

26 ! Big[(k-1)*10+(1:10),1:(sum(censored=1)+1)]=survival1*t(t); end; create GIB_&p from

26 ! BIG[colname={COL1}]; append from BIG; quit; ; end; *print InverseC;

---

180

ERROR 180-322: Statement is not valid or it is used out of proper order.

proc iml;

use man;

read all var{ Replicate time censored obs y Frequency SURVIVAL1 SurvivalM InverseC } into DM;

close; /*close the link between the dataset and IML*/

InverseC=DM[,9];SurvivalM=DM[,8];survival1=DM[,7]; frequency=DM[,6]; y=DM[,5];obs =DM[,4]; censored=DM[,3]; time= DM[,2]; replicate = DM[,1]; /*Survivalival is second column*/ /*time is first column*/

n = nrow(byGroup);

u = unique(Replicate);

BIG=J(20,10,-1) ;

InverseC=J(nrow(survival1),1,1);

survival1= J(nrow(survival1),1,1);

t=J(nrow(survival1),1,1);

do k = 1 to nrow(byGroup);

byGroup = DM[loc(replicate=u),];

InverseC=byGroup[,9];SurvivalM=byGroup[,8]; survival1=byGroup[,7];frequency=byGroup[,6];y=byGroup[,10];obs =byGroup[,4]; censored =byGroup[,3]; time= byGroup[,2]; replicate= byGroup[,1];

t=InverseC[(loc(InverseC^=0))]; print t;

tt=t(t); print tt;

Big[(k-1)*10+(1:10),1:(sum(censored=1)+1)]=survival1*(tt);

end;

create GIB_1 from BIG[colname={COL1}];

append from BIG;

quit;

Re: statement not valid or used out of proper order

ballardw — Wed, 06 Nov 2013 23:55:46 GMT

Looks like end of comment without a starting /*

Re: statement not valid or used out of proper order

desireatem — Thu, 07 Nov 2013 00:04:36 GMT

I start with a do...

end;

see below;

do k = 1 to nrow(byGroup);

byGroup = DM[loc(replicate=u),];

InverseC=byGroup[,9];SurvivalM=byGroup[,8]; survival1=byGroup[,7];frequency=byGroup[,6];y=byGroup[,10];obs =byGroup[,4]; censored =byGroup[,3]; time= byGroup[,2]; replicate= byGroup[,1];

t=InverseC[(loc(InverseC^=0))]; print t;

tt=t(t); print tt;

Big[(k-1)*10+(1:10),1:(sum(censored=1)+1)]=survival1*(tt);

end;

Re: statement not valid or used out of proper order

Reeza — Thu, 07 Nov 2013 00:32:03 GMT

The log shows append and quit, which I don't see in your code, so that's strange.

Can you post the whole log/code.

Re: statement not valid or used out of proper order

desireatem — Thu, 07 Nov 2013 01:06:47 GMT

This is within a simulation, I run it for just one iteration, that is &p=1. The code has append and quit. Your help is highly need Sir

Here is the log file:

data KMM_&p;

570 set testt_&p;

571 set KM_&p;

572 if censored=1 then SurvivalM=Survival1; else SurvivalM=Survival1;

573 if censored=1 then InverseC=1/survival1; else InverseC=0;

574 keep time censored y frequency survival1 obs replicate SurvivalM InverseC;

575 run;

576

577

578 proc iml;

579 use KMM_&p;

580 read all var{ Replicate time censored obs y Frequency SURVIVAL1 SurvivalM InverseC } into

580! DM;

581 close;

581! /*close the link between the dataset and IML*/

582 InverseC=DM[,9];SurvivalM=DM[,8];survival1=DM[,7]; frequency=DM[,6]; y=DM[,5];obs

582! =DM[,4]; censored=DM[,3]; time= DM[,2]; replicate = DM[,1]; /*Survivalival is second

582! column*/ /*time is first column*/

583

584 n = nrow(byGroup);

585 u = unique(Replicate);

586 BIG=J(20,10,-1) ;

587 InverseC=J(nrow(survival1),1,1);

588 survival1= J(nrow(survival1),1,1);

589 t=J(nrow(survival1),1,1);

590 do k = 1 to nrow(byGroup);

591 byGroup = DM[loc(replicate=u),];

592 *byIdx = loc(Replicate=u); /* the UNIQUE-LOC trick */

593 *byGroup = DM[byIdx,]; /* extract BY group */ /* extract BY group

593! */

594 InverseC=byGroup[,9];SurvivalM=byGroup[,8]; survival1=byGroup[,7];

594! frequency=byGroup[,6];y=byGroup[,10];obs =byGroup[,4]; censored =byGroup[,3]; time=

594! byGroup[,2]; replicate= byGroup[,1];

595 t=InverseC[(loc(InverseC^=0))]; print t;

596 tt=t(t); *print tt;

597 Big[(k-1)*10+(1:10),1:(sum(censored=1)+1)]=survival1*t(t);

598 end;

599

600

601 create GIB_&p from BIG[colname={COL1}];

602 append from BIG;

603 quit;

604

605

606

OTE: There were 20 observations read from the data set WORK.TESTT_1.

NOTE: There were 20 observations read from the data set WORK.KM_1.

NOTE: The data set WORK.KMM_1 has 20 observations and 9 variables.

NOTE: DATA statement used (Total process time):

real time 0.00 seconds

cpu time 0.00 seconds

NOTE: IML Ready

NOTE: Closing WORK.KMM_1

NOTE: Exiting IML.

NOTE: The data set WORK.GIB_1 has 20 observations and 10 variables.

NOTE: PROCEDURE IML used (Total process time):

real time 0.01 seconds

cpu time 0.01 seconds

NOTE: Line generated by the invoked macro "SURV".

26 (InverseC^=0))]; print t; tt=t(t); *print tt;

26 ! Big[(k-1)*10+(1:10),1:(sum(censored=1)+1)]=survival1*t(t); end; create GIB_&p from

26 ! BIG[colname={COL1}]; append from BIG; quit; ; end; *print InverseC;

---

180

ERROR 180-322: Statement is not valid or it is used out of proper order.