topic Re: Unique count for in SAS Enterprise Guide

Unique count for

Haydn — Wed, 20 Sep 2017 03:12:26 GMT

Hi All,

Sample data below

Ref	InvoiceNumber	InvoiceType	Reason
123	A1	NAA	Income
123	A2	NAA	Income
123	A3	DPP	Income
123	A4	PPA	Care

I would like to do a unique count combing Ref and InvoiceType and a unique count combing Ref and Reason. Output should be as below.

Ref	InvoiceNumber	InvoiceType	Reason	UnqiueRef	UniqueReason	UniqueInvoiceType
123	A1	NAA	Income	1	1	1
123	A2	NAA	Income
123	A3	DPP	Income			1
123	A4	PPA	Care		1	1

I had thought of concatenating Ref and InvoiceType (new field UniqueInvoiceType) and also Ref and Reason (new field UniqueReason) and doing an if first on both thos fields.

Is this the best/most efficient way of achiveing this?

Cheers

Haydn

Re: Unique count for

kiranv_ — Wed, 20 Sep 2017 05:50:47 GMT

I am very sure, there will be much easier and cleaner solution then what I have written. if your combination of ref and invoicenumber are unique then you can do sperately each first.group and then join them back as shown below.

data have;
input Ref $ 1-3 InvoiceNumber $ 5-6	InvoiceType $ 8-10	Reason $ 12-18;
datalines;
123	A1	NAA	Income
123	A2	NAA	Income
123	A3	DPP	Income
123	A4	PPA	Care
223	A1	NAA	Income
223	A2	NAA	Income
223	A3	DPP	Income
223	A4	PPA	Care
;

proc sort data = have out=have1;
by Ref invoicenumber;
run;

data have1a;
set have1;
by Ref invoicenumber;
if first.ref then UnqiueRef = 1; else UnqiueRef =.;
 run;
 
 proc sort data = have out=have2;
by Ref  InvoiceType;
run;
 
 data have2a;
set have2;
by Ref  InvoiceType;
if first.invoicetype = 1 then UniqueInvoiceType =1 ; 
 else UniqueInvoiceType =.;
 run;
 
  proc sort data = have out=have3;
by Ref reason;
run;
 
 data have3a;
set have3;
by Ref  reason;
if first.reason = 1 then Uniquereason =1 ; 
 else Uniquereason =.;
 run;
 
 
 proc sql;
 create table want as
 select a.Ref,
        a.invoicenumber,
        a.invoicetype,
        a.reason,
        a.UnqiueRef,
        b.UniqueInvoiceType,
        c.Uniquereason
 from have1a a, have2a b, have3a c
 where  a.Ref = b.ref
 and    a.ref=c.ref
 and   a.InvoiceNumber =b.InvoiceNumber
 and    a.InvoiceNumber =c.InvoiceNumber
 order by a.Ref, a.InvoiceNumber;
 quit;

Re: Unique count for

Ksharp — Wed, 20 Sep 2017 13:37:06 GMT

I love this question. What if there are more than one Ref ?


data have;
input Ref $ 1-3 InvoiceNumber $ 5-6	InvoiceType $ 8-10	Reason $ 12-18;
datalines;
123	A1	NAA	Income
123	A2	NAA	Income
123	A3	DPP	Income
123	A4	PPA	Care
223	A1	NAA	Income
223	A2	NAA	Income
223	A3	DPP	Income
223	A4	PPA	Care
;

data want;
 if _n_=1 then do;
  if 0 then set have;
  declare hash h1(dataset:'have');
  h1.definekey('ref');
  h1.definedone();

  declare hash h2(dataset:'have');
  h2.definekey('ref','InvoiceType');
  h2.definedone();

  declare hash h3(dataset:'have');
  h3.definekey('ref','Reason');
  h3.definedone();
 end;
set have;
if h1.check()=0 then do;UnqiueRef=1;h1.remove();end;
if h2.check()=0 then do;UniqueReason=1;h2.remove();end;
if h3.check()=0 then do;UniqueInvoiceType=1;h3.remove();end;
run;

Re: Unique count for

Haydn — Wed, 20 Sep 2017 23:39:01 GMT

Thanks for your help on this.

There will definitely be more than 1 ref in the dataset (it has 2 million rows). I'm running this now and will post back here on how it went.

Cheers

Haydn

Re: Unique count for

Haydn — Thu, 21 Sep 2017 03:17:27 GMT

Thanks for you help, your code worked like a charm