topic Assigning Inpatient first date to interim bills with a 1 day gap in SAS Programming

Assigning Inpatient first date to interim bills with a 1 day gap

allores — Sat, 15 Jul 2017 11:51:11 GMT

Below is a snap shot of the table, obviously it’s bigger than this, but these are the fields I need to use. The issue is that lines 3 and 4 are all 1 inpatient stay, with just an interim bill submitted with a 1 day "gap". Lines 1, 2, 5 are all discrete IP stays.

I need to group lines 3 and 4 and assign 06/15/2017 as the IP_START_DATE to both so that a “visit”: would be (123456||06/15/2017||987654) for all lines 3 and 4. The other part of this is that it is not always just two lines, it could be 3 or more that all combine to a > 90 day stay with interim bills so the lag function doesn't seem to be working for me.

Index	Member ID	DOS Start	DOS End	Provider ID
OBS	FK_PTY_ID	MEDI_START_DATE	MEDI_END_DATE	HOSP_CODE
1	12345	02/01/2017	02/01/2017	987654
2	12345	03/01/2017	03/10/2017	987654
3	12345	06/15/2017	06/30/2017	987654
4	12345	07/01/2017	07/10/2017	987654
5	12345	08/20/2017	08/24/2017	987654

My idea was to make a “sub_visit” of (FK_PTY_ID||HOSP_CODE), sort by that, then list all the MEDI_START_DATE by ascending and get the “gap” from MEDI_END_DATE to MEDI_START_DATE2 (lagged). If that “gap” is <= 1 then consider it all one visit. If not, it’s a new visit. Something like this:

Index	Member ID	DOS Start	DOS End	Provider ID	Created	Created
OBS	FK_PTY_ID	MEDI_START_DATE	MEDI_END_DATE	HOSP_CODE	SUB_VISIT	GAP
1	12345	02/01/2017	02/01/2017	987654	12345987654	.
2	12345	03/01/2017	03/10/2017	987654	12345987654	30
3	12345	06/15/2017	06/30/2017	987654	12345987654	97
4	12345	07/01/2017	07/10/2017	987654	12345987654	1
5	12345	08/20/2017	08/24/2017	987654	12345987654	41

Then, reading back it will look for a gap <= to 1 and assign the first MEDI_START_DATE within that visit only. (without reading all the way back to line 1, b/c is was the same member at the same provider but a very different visit months before.)

Index	Member ID	DOS Start	DOS End	Provider ID	Created	Created	Created
OBS	FK_PTY_ID	MEDI_START_DATE	MEDI_END_DATE	HOSP_CODE	SUB_VISIT	GAP	IP_START
1	12345	02/01/2017	02/01/2017	987654	12345987654	.	02/01/2017
2	12345	03/01/2017	03/10/2017	987654	12345987654	30	03/01/2017
3	12345	06/15/2017	06/30/2017	987654	12345987654	97	06/15/2017
4	12345	07/01/2017	07/10/2017	987654	12345987654	1	06/15/2015
5	12345	08/20/2017	08/24/2017	987654	12345987654	41	08/20/2017

I had been trying to use code like this, but it will pnly look back one line.

PROC SORT DATA=ALLORES.SUB_VISIT OUT=ALLORES.SUB_VISIT;

BY SUB_VISIT;

BY MEDI_START_DATE;

RUN;

DATA SUB_VISIT;

SET WORK.SUB_VISIT;

MEDI_S1= MEDI_START_DATE;

MEDI_S2 = LAG(MEDI_START_DATE);

MEDI_E1 = MEDI_END_DATE;

MEDI_E2 = LAG(MEDI_END_DATE);

GAP = MEDI_E1 - MEDI_S2;

IF FK_PTY_ID = LAG(FK_PTY_ID)

AND HOSP_CODE = LAG(HOSP_CODE)

AND GAP <= 1

THEN IP_START_DATE = put(MEDI_START_DATE,yymmdd10.);

ELSE IP_START_DATE = put(lag(MEDI_START_DATE),yymmdd10.);

RUN;

Thanks in adance!

Re: Assigning Inpatient first date to interim bills with a 1 day gap

Astounding — Sat, 15 Jul 2017 13:43:21 GMT

A few things stand out about your question. Areas to learn more:

First, become more comfortable with dates. When creating IP_START_DATE, there is no need to create it as a character variable. Keep it as a numeric SAS date, and apply a format to it.

Second, as you have seen the LAG function won't handle everything. Sometimes it won't even give the right answer. If you want to retrieve the value on the previous observation, LAG has to execute on every observation (outside of any IF/THEN conditions).

Third, learning the use of a BY statement in a DATA step is vital. There's more to learn than can be posted here, but it is vital.

All that being said, let's take a look at the problem you posted. Here is a variation on what you posted that works with the original data set (without adding SUB_VISIT):

proc sort data=original_data_set;

by fk_pty_id hosp_code;

run;

The following approach will get you part-way there by assigning observations to a visit, based on the gap. Other calculations (such as when does the visit begin, when does it end) are not included here:

data want;

set original_data_set;

by fk_pty_id hosp_code;

gap = medi_end_date - lag(medi_start_date);

if first.fk_pty_id then visit = 1;

else if first.hosp_code or gap > 1 then visit + 1;

run;

Take a look at just that much, and see how close it gets you to where you need to go with this.

Re: Assigning Inpatient first date to interim bills with a 1 day gap

allores — Sun, 16 Jul 2017 02:50:39 GMT

Thank You! This worked as a step to what I needed to get to. I switched gap to = medi_start - lag(medi_end). I appreciate the help and I am also going to learn more about the 3 bullets in your response.