Get each last day of preceding months

philip_ — Thu, 06 Jul 2017 08:04:28 GMT

Hello,

I wanted to create a dataset called timestamps that lists the last day of each month of the preceding 6 months. My solution for this is:

DATA timestamps;
	d = today();
	format d date9.;
  	DO i=0 TO 5;
  		d = intnx('month',d,-i)-1;
  		output;
  	END;
run;

However, I get this as result:

If I "rerun the loop manually", I get the day I expect. E.g. this code

DATA timestamps;
	d = today();
	format d date9.;
  	d = intnx('month',d,-1)-1;
run;

gives: 31MAY2017

Why do I get 30APR2017 for i =1 in the loop? What is wrong in my loop?

Thanks for the help!

Kind regards,
philip

Re: Get each last day of preceding months

RW9 — Thu, 06 Jul 2017 08:17:42 GMT

At a guess your changing the variable your working on, try:

data timestamps;
  d = today();
  format d dt date9.;
  do i=0 to 5;
    dt=intnx('month',d,-i)-1;
    output;
  end;
run;