topic Re: Extract file name in SAS Programming

Extract file name

tparrent — Mon, 26 Jun 2017 19:49:33 GMT

I have a very simple program that reads in the contents of all the .csv files in a Windows directory. That part of the program works fine.

I would like to add the file name to each record.

The problem I have is the variable fullfilename contains only 'C:\Users' rather than the full name. I have verified this with PUT statements.

In the log, SAS correctly identifies the full path and name and the proper data is imported but the ticker field (to wihich I tried to assign the parsed filename) is blank, as is the fullfilename field.

Thanks for your help!

Using Windows 10 and SAS 9.4 in Enterprise Guide

data ticker_files;
infile 'c:\Users\tparrent\Documents\SandP 500 Stock History\daily\table_*.csv'
   FILENAME=fullfilename
   DELIMITER=','
   FIRSTOBS=1;
put fullfilename;

do until(last);

   input dateint unknown open high low close volume;
   ticker = scan(scan(fullfilename,-1,'_'),1,'.');
   output;
end;

Re: Extract file name

Reeza — Mon, 26 Jun 2017 20:05:27 GMT

When you use the FILENAME you need to actually store it, I don't see that in your code, but it doesn't look complete either....

This is what you'd add and you should have a variable called sourceFile in your dataset. I don't even think fullFileName would be outputted to your dataset otherwise.

sourceFile = fullFileName;

Re: Extract file name

tparrent — Mon, 26 Jun 2017 20:14:11 GMT

I tried your sugestions and sourceFileName still contains only 'C:\Users'

I did post the entire code and it does run and import the data from the files

Re: Extract file name

Reeza — Mon, 26 Jun 2017 20:20:41 GMT

make sure to specify the length as well.

length fullFileName sourceName $256.;

Re: Extract file name

tparrent — Mon, 26 Jun 2017 20:29:14 GMT

LENGTH fullfilename $256.; did the trick!

Thank you very much Reeza. I now understand something beyond the specific problem - don't get careless with variables!