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    <title>topic How to find the value of two independent variables that make the dependent variable is minimum in SAS Programming</title>
    <link>https://communities.sas.com/t5/SAS-Programming/How-to-find-the-value-of-two-independent-variables-that-make-the/m-p/330075#M73966</link>
    <description>&lt;P&gt;Hi SAS community members,&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;I am trying to find out the values of two independent variables that make the value of dependent variable is minimum.&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;For example, here is my equation: EC= q1(x1)c1+q2(x2)c2&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;what i want to do is find out the values of x1 and x2 that make EC is the minimum.&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;Could anyone please help me for this .&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;Many thanks for your help.&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;Regards,&lt;/P&gt;&lt;P&gt;Terrence&lt;/P&gt;</description>
    <pubDate>Mon, 06 Feb 2017 01:33:30 GMT</pubDate>
    <dc:creator>Terrencefung</dc:creator>
    <dc:date>2017-02-06T01:33:30Z</dc:date>
    <item>
      <title>How to find the value of two independent variables that make the dependent variable is minimum</title>
      <link>https://communities.sas.com/t5/SAS-Programming/How-to-find-the-value-of-two-independent-variables-that-make-the/m-p/330075#M73966</link>
      <description>&lt;P&gt;Hi SAS community members,&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;I am trying to find out the values of two independent variables that make the value of dependent variable is minimum.&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;For example, here is my equation: EC= q1(x1)c1+q2(x2)c2&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;what i want to do is find out the values of x1 and x2 that make EC is the minimum.&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;Could anyone please help me for this .&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;Many thanks for your help.&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;Regards,&lt;/P&gt;&lt;P&gt;Terrence&lt;/P&gt;</description>
      <pubDate>Mon, 06 Feb 2017 01:33:30 GMT</pubDate>
      <guid>https://communities.sas.com/t5/SAS-Programming/How-to-find-the-value-of-two-independent-variables-that-make-the/m-p/330075#M73966</guid>
      <dc:creator>Terrencefung</dc:creator>
      <dc:date>2017-02-06T01:33:30Z</dc:date>
    </item>
    <item>
      <title>Re: How to find the value of two independent variables that make the dependent variable is minimum</title>
      <link>https://communities.sas.com/t5/SAS-Programming/How-to-find-the-value-of-two-independent-variables-that-make-the/m-p/330083#M73971</link>
      <description>&lt;P&gt;1) please post a smaple of your data for test.&lt;/P&gt;
&lt;P&gt;2) how many observationsare in your dataset ?&lt;/P&gt;
&lt;P&gt;3) have you tried to create a sas code ? If yes - post it.&lt;/P&gt;</description>
      <pubDate>Mon, 06 Feb 2017 02:21:15 GMT</pubDate>
      <guid>https://communities.sas.com/t5/SAS-Programming/How-to-find-the-value-of-two-independent-variables-that-make-the/m-p/330083#M73971</guid>
      <dc:creator>Shmuel</dc:creator>
      <dc:date>2017-02-06T02:21:15Z</dc:date>
    </item>
    <item>
      <title>Re: How to find the value of two independent variables that make the dependent variable is minimum</title>
      <link>https://communities.sas.com/t5/SAS-Programming/How-to-find-the-value-of-two-independent-variables-that-make-the/m-p/330095#M73978</link>
      <description>&lt;P&gt;Hi Shmuel,&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;Thank you very much for your prompt response. Some variables of the equation are known,&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;The sample data as follow:&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;TABLE border="0" cellspacing="0" cellpadding="0"&gt;&lt;TBODY&gt;&lt;TR&gt;&lt;TD&gt;Global Company&lt;/TD&gt;&lt;TD&gt;em&lt;/TD&gt;&lt;TD&gt;Estimated Probability&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;Key&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;&amp;nbsp;&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;&amp;nbsp;&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;1173&lt;/TD&gt;&lt;TD&gt;1&lt;/TD&gt;&lt;TD&gt;0.01095&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;1173&lt;/TD&gt;&lt;TD&gt;1&lt;/TD&gt;&lt;TD&gt;0.00952&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;1286&lt;/TD&gt;&lt;TD&gt;1&lt;/TD&gt;&lt;TD&gt;0.00804&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;3362&lt;/TD&gt;&lt;TD&gt;1&lt;/TD&gt;&lt;TD&gt;0.0161&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;3734&lt;/TD&gt;&lt;TD&gt;0&lt;/TD&gt;&lt;TD&gt;0.00812&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;3839&lt;/TD&gt;&lt;TD&gt;1&lt;/TD&gt;&lt;TD&gt;0.0123&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;3946&lt;/TD&gt;&lt;TD&gt;1&lt;/TD&gt;&lt;TD&gt;0.01109&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;4060&lt;/TD&gt;&lt;TD&gt;0&lt;/TD&gt;&lt;TD&gt;0.00972&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;4060&lt;/TD&gt;&lt;TD&gt;1&lt;/TD&gt;&lt;TD&gt;0.01077&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;4372&lt;/TD&gt;&lt;TD&gt;1&lt;/TD&gt;&lt;TD&gt;0.00967&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;4601&lt;/TD&gt;&lt;TD&gt;1&lt;/TD&gt;&lt;TD&gt;0.00978&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;4601&lt;/TD&gt;&lt;TD&gt;0&lt;/TD&gt;&lt;TD&gt;0.00981&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;4622&lt;/TD&gt;&lt;TD&gt;1&lt;/TD&gt;&lt;TD&gt;0.00922&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;4769&lt;/TD&gt;&lt;TD&gt;1&lt;/TD&gt;&lt;TD&gt;0.01033&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;5047&lt;/TD&gt;&lt;TD&gt;1&lt;/TD&gt;&lt;TD&gt;0.01023&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;5399&lt;/TD&gt;&lt;TD&gt;1&lt;/TD&gt;&lt;TD&gt;0.00945&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;6136&lt;/TD&gt;&lt;TD&gt;1&lt;/TD&gt;&lt;TD&gt;0.01154&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;6136&lt;/TD&gt;&lt;TD&gt;1&lt;/TD&gt;&lt;TD&gt;0.00984&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;6882&lt;/TD&gt;&lt;TD&gt;1&lt;/TD&gt;&lt;TD&gt;0.00917&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;7652&lt;/TD&gt;&lt;TD&gt;1&lt;/TD&gt;&lt;TD&gt;0.00949&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;7652&lt;/TD&gt;&lt;TD&gt;0&lt;/TD&gt;&lt;TD&gt;0.00958&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;7991&lt;/TD&gt;&lt;TD&gt;1&lt;/TD&gt;&lt;TD&gt;0.01051&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;8092&lt;/TD&gt;&lt;TD&gt;1&lt;/TD&gt;&lt;TD&gt;0.01075&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;8972&lt;/TD&gt;&lt;TD&gt;0&lt;/TD&gt;&lt;TD&gt;0.01&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;9538&lt;/TD&gt;&lt;TD&gt;1&lt;/TD&gt;&lt;TD&gt;0.01213&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;10026&lt;/TD&gt;&lt;TD&gt;1&lt;/TD&gt;&lt;TD&gt;0.00946&lt;/TD&gt;&lt;/TR&gt;&lt;/TBODY&gt;&lt;/TABLE&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;em=1means the observations is a manipulator, 0 otherwise, &amp;nbsp;&lt;SPAN&gt;Estimated Probability is the estmated probabilty calculated by a Logit model.&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;&amp;nbsp;I need to find a cut-off value for&amp;nbsp;&lt;SPAN&gt;Estimated Probability that make EC has the minimum value&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN&gt;EC= q1(x1)c1+q2(x2)c2 &lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN&gt;where q1=0.01, c1=1 , q2=0.99, c2=20&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN&gt;x1 is the observed Type I error, x2 is the observed the Type II error.&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;&lt;SPAN&gt;I have 10,000 observations.&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;&lt;SPAN&gt;Thank you again for your reply.&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;&lt;SPAN&gt;Kind regards,&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN&gt;Terrence&amp;nbsp;&lt;/SPAN&gt;&lt;/P&gt;</description>
      <pubDate>Mon, 06 Feb 2017 04:40:29 GMT</pubDate>
      <guid>https://communities.sas.com/t5/SAS-Programming/How-to-find-the-value-of-two-independent-variables-that-make-the/m-p/330095#M73978</guid>
      <dc:creator>Terrencefung</dc:creator>
      <dc:date>2017-02-06T04:40:29Z</dc:date>
    </item>
    <item>
      <title>Re: How to find the value of two independent variables that make the dependent variable is minimum</title>
      <link>https://communities.sas.com/t5/SAS-Programming/How-to-find-the-value-of-two-independent-variables-that-make-the/m-p/330096#M73979</link>
      <description>&lt;P&gt;Are q1 and q2 continuous functions? If so, can you find their derivative?&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;P&gt;Do you have a licence for&amp;nbsp;SAS/OR?&lt;/P&gt;</description>
      <pubDate>Mon, 06 Feb 2017 04:31:04 GMT</pubDate>
      <guid>https://communities.sas.com/t5/SAS-Programming/How-to-find-the-value-of-two-independent-variables-that-make-the/m-p/330096#M73979</guid>
      <dc:creator>PGStats</dc:creator>
      <dc:date>2017-02-06T04:31:04Z</dc:date>
    </item>
    <item>
      <title>Re: How to find the value of two independent variables that make the dependent variable is minimum</title>
      <link>https://communities.sas.com/t5/SAS-Programming/How-to-find-the-value-of-two-independent-variables-that-make-the/m-p/330097#M73980</link>
      <description>&lt;P&gt;Hi PG STATS,&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;Thank you for your reply.&lt;/P&gt;&lt;P&gt;q1 and q2 are assumed probabilities, and not &lt;SPAN&gt;continuous&lt;/SPAN&gt;. For example, here i assume the assuemd probabilty for manipulator q1=0.01 (1%), and the assumend probabilty for non-manipulator is q2=0.99 (99%).&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;Yes, I have the licence for SAS/OR.&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;Thank you for your help.&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;</description>
      <pubDate>Mon, 06 Feb 2017 04:44:54 GMT</pubDate>
      <guid>https://communities.sas.com/t5/SAS-Programming/How-to-find-the-value-of-two-independent-variables-that-make-the/m-p/330097#M73980</guid>
      <dc:creator>Terrencefung</dc:creator>
      <dc:date>2017-02-06T04:44:54Z</dc:date>
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