topic Re: Question on arithmetic conversion in SAS Programming

Question on arithmetic conversion

wetzer123 — Thu, 24 Nov 2016 08:43:38 GMT

Hello,

I am pretty new to SAS but I hve to maintain some older programs. Now I am stuck with a problem.

I have a program that does this:

PROC MEANS NOPRINT;
VAR AMOUNT AVG1 AVG2;
BY OBJNAME;
OUTPUT OUT=WORK.SUMM1
SUM(AMOUNT) = AMOUNT
MEAN(AVG1 AVG2) =
AVG1 AVG2 ;

Sadly the input data of AVG1 and AVG2 is not an average at all but the cumulated data, so to get real averages at the end I would have to do sum up AVG1 and AVG2 for each OBJNAME and divide it by AMOUNT.

If I do

PROC MEANS NOPRINT;
VAR AMOUNT AVG1 AVG2;
BY OBJNAME;
OUTPUT OUT=WORK.SUMM1
SUM(AMOUNT) = AMOUNT
SUM(AVG1 AVG2) =
AVG1 AVG2 ;

it looks nice but I still need the division, my idea was putting in something like

AVG1= AVG1/AMOUNT

but I didn't find a way how this could work.

Maybe someone van give me a hint how to do this?

Re: Question on arithmetic conversion

Kurt_Bremser — Thu, 24 Nov 2016 09:11:37 GMT

data summ1;
set dataset (rename=(
  amount=oldamount
  avg1=oldavg1
  avg2=oldavg2
));
by objname;
if first.objname
then do;
  amount = 0;
  avg1 = 0;
  avg2 = 0;
end;
amount + oldamount;
avg1 + oldavg1;
avg2 + oldavg2;
if last.objname
then do;
  avg1 = avg1 / amount;
  avg2 = avg2 / amount;
  output;
end;
drop oldamount oldavg1 oldavg2;
run;

"Manual" solution.

Re: Question on arithmetic conversion

wetzer123 — Thu, 24 Nov 2016 09:50:57 GMT

I will have to check this, as I am not shure wether it will no confuse with my data step.

Re: Question on arithmetic conversion

Kurt_Bremser — Thu, 24 Nov 2016 09:53:27 GMT

Unless you make use of the auomatically created _type_ and _freq_ variables, you should get the right output.