topic Re: Controlling Variable Suffix by Creating New Variables with an Array in SAS Programming

Controlling Variable Suffix by Creating New Variables with an Array

kevinmc87 — Tue, 26 Jul 2016 15:35:30 GMT

Hi,

I'm trying to create new variables with an array statement that contain suffixes that match from a previously referenced array statement. This is my code:

DATA BLAH_F7;
	SET BLAH_F;
	ARRAY A[0:100]F_0--F_100;
	ARRAY P_[0:100]P_0--P_100;
		DO I=0 TO 100;
		P_(I)=A(I)/F_TOTAL;
	END;
	DROP I;
RUN;

When I run this code, the array creates variables P_1 to P_101 instead of from P_0 to P_100, which is what I want (as I am trying to match to the F_0 to F_100 variables). Anyone have any suggestions? If this isn't possible using an array statement, I'd still be interested in hearing the simplest way to change these P_1 to P_101 variables to P_0 to P_100.

Thanks.

Re: Controlling Variable Suffix by Creating New Variables with an Array

Reeza — Tue, 26 Jul 2016 15:37:47 GMT

Try the following, though I would have thought that P0-P100 would work.

Array p_(0:100) p0 p1-p100;

Re: Controlling Variable Suffix by Creating New Variables with an Array

kevinmc87 — Tue, 26 Jul 2016 15:43:51 GMT

Thanks, this solution works. I guess P_0 needs to be explicitly stated since this is an array statement that isn't referencing any previously exisiting variables? I'm a little confused by why this works:

Array p_(0:100) p0 p1-p100;

but this doesn't work:

Array p_(0:100) p0-p100;

Thanks for your help!

Re: Controlling Variable Suffix by Creating New Variables with an Array

Astounding — Tue, 26 Jul 2016 15:50:06 GMT

Both of those should work.

The piece that doesn't work is the double dash. For SAS to interpret the double dash properly, the variables must already exist and cannot be created by the ARRAY statement.

Re: Controlling Variable Suffix by Creating New Variables with an Array

kevinmc87 — Tue, 26 Jul 2016 16:06:09 GMT

Thanks, Astouding. I did not realize this.