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    <title>topic Re: distinct id's in SAS Programming</title>
    <link>https://communities.sas.com/t5/SAS-Programming/distinct-id-s/m-p/29325#M5513</link>
    <description>Thanks Patrick.</description>
    <pubDate>Fri, 05 Nov 2010 20:52:51 GMT</pubDate>
    <dc:creator>SASPhile</dc:creator>
    <dc:date>2010-11-05T20:52:51Z</dc:date>
    <item>
      <title>distinct id's</title>
      <link>https://communities.sas.com/t5/SAS-Programming/distinct-id-s/m-p/29322#M5510</link>
      <description>Dataset A has a million Id's and Dataset B has million id's.&lt;BR /&gt;
how to find the count of distinct id's that are common in two datasets?</description>
      <pubDate>Fri, 05 Nov 2010 14:27:27 GMT</pubDate>
      <guid>https://communities.sas.com/t5/SAS-Programming/distinct-id-s/m-p/29322#M5510</guid>
      <dc:creator>SASPhile</dc:creator>
      <dc:date>2010-11-05T14:27:27Z</dc:date>
    </item>
    <item>
      <title>Re: distinct id's</title>
      <link>https://communities.sas.com/t5/SAS-Programming/distinct-id-s/m-p/29323#M5511</link>
      <description>PROC SQL - two SELECT DINSTINCT(keyvar1 keyvar2), one for each file and then a JOIN, possibly using a sub-query in the process.&lt;BR /&gt;
&lt;BR /&gt;
For a DATA step approach, suggesting setting a VIEW for each file, then do two PROC SORT NODUPKEY with your BY variable list, then a MERGE with a BY statement, and using the IN= dataset option, you can then test your IN= variables for both files contributing to the MERGE.&lt;BR /&gt;
&lt;BR /&gt;
Scott Barry&lt;BR /&gt;
SBBWorks, Inc.</description>
      <pubDate>Fri, 05 Nov 2010 14:55:20 GMT</pubDate>
      <guid>https://communities.sas.com/t5/SAS-Programming/distinct-id-s/m-p/29323#M5511</guid>
      <dc:creator>sbb</dc:creator>
      <dc:date>2010-11-05T14:55:20Z</dc:date>
    </item>
    <item>
      <title>Re: distinct id's</title>
      <link>https://communities.sas.com/t5/SAS-Programming/distinct-id-s/m-p/29324#M5512</link>
      <description>Hi&lt;BR /&gt;
&lt;BR /&gt;
A SQL approach:&lt;BR /&gt;
&lt;BR /&gt;
data haveA;&lt;BR /&gt;
  do id=1,2,2,3,4,5,5,5,6;&lt;BR /&gt;
    output;&lt;BR /&gt;
  end;&lt;BR /&gt;
run;&lt;BR /&gt;
&lt;BR /&gt;
data haveB;&lt;BR /&gt;
  do id=1,1,1,3,3,4,6;&lt;BR /&gt;
    output;&lt;BR /&gt;
  end;&lt;BR /&gt;
run;&lt;BR /&gt;
&lt;BR /&gt;
proc sql feedback;&lt;BR /&gt;
  select COUNT(*) as N_UniqueIds&lt;BR /&gt;
    from &lt;BR /&gt;
      ( select distinct id from work.haveA) as A,&lt;BR /&gt;
      ( select distinct id from work.haveB) as B&lt;BR /&gt;
   where A.id = B.id;&lt;BR /&gt;
  ;&lt;BR /&gt;
quit;&lt;BR /&gt;
&lt;BR /&gt;
&lt;BR /&gt;
HTH&lt;BR /&gt;
Patrick</description>
      <pubDate>Fri, 05 Nov 2010 20:06:43 GMT</pubDate>
      <guid>https://communities.sas.com/t5/SAS-Programming/distinct-id-s/m-p/29324#M5512</guid>
      <dc:creator>Patrick</dc:creator>
      <dc:date>2010-11-05T20:06:43Z</dc:date>
    </item>
    <item>
      <title>Re: distinct id's</title>
      <link>https://communities.sas.com/t5/SAS-Programming/distinct-id-s/m-p/29325#M5513</link>
      <description>Thanks Patrick.</description>
      <pubDate>Fri, 05 Nov 2010 20:52:51 GMT</pubDate>
      <guid>https://communities.sas.com/t5/SAS-Programming/distinct-id-s/m-p/29325#M5513</guid>
      <dc:creator>SASPhile</dc:creator>
      <dc:date>2010-11-05T20:52:51Z</dc:date>
    </item>
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