topic Hash Question in SAS Programming

Hash Question

redfishJAX — Tue, 08 Dec 2015 15:21:37 GMT

The following script selects the first payment that meets the criteria of the given promise record by using a hash table. I need to modify this to render ALL records in the payment table that meet the promise criteria.

So for the first record in promise (acctnum = 100 dated 3/15) - i would see two payments (dated 3/21 and 3/25) for that promise record in the output. no records would be output for the second observation (acctnum = 100 dated 3/21).

Can the below script modified to accomplish this?

data Promise ;
input acctnum promisedate : mmddyy12. promiseamt (bwindow ewindow ) (: mmddyy12.);
format promisedate bwindow ewindow mmddyy10.;
cards;
100 3/15/2015 100 3/15/2015 3/28/2015
100 3/21/2015 150 3/21/2015 4/1/2015
200 3/15/2015 100 3/15/2015 3/28/2015
200 3/21/2015 150 3/21/2015 4/1/2015
;
run;

data Payments ;
input acctnum paydate : mmddyy12. payamt ;
format paydate mmddyy10.;
cards;
100 3/21/2015 100
100 3/25/2015 150
100 5/25/2015 150
200 3/21/2015 100
200 3/25/2015 150
200 3/28/2015 150
200 5/25/2015 150
;
run;

data want;
if _n_ eq 1 then do;
if 0 then set Promise(keep=acctnum bwindow ewindow);
declare hash h(dataset:'Promise(keep=acctnum bwindow ewindow)',multidata&colon;'y');
h.definekey('acctnum');
h.definedata('bwindow','ewindow');
h.definedone();
end;
set Payments;
rc=h.find();
do while(rc=0);
if bwindow le paydate le ewindow then do;
                                          found=1;
                                                  h.removedup();
                                          leave;
                                       end;
rc=h.find_next();
end;
drop rc;
run;

Re: Hash Question

Steelers_In_DC — Tue, 08 Dec 2015 15:42:10 GMT

I am missing something, can you explain why the second record does not fall into the criteria?

Re: Hash Question

redfishJAX — Tue, 08 Dec 2015 15:49:16 GMT

Once a payment record/observation has been used.. i dont want to use it again for any further observation in the promise dataset.

The first two obs of the payment dataset would go witht the first observation in the promise dataset. The second observation in the promise dataset would get no matches.

Re: Hash Question

Steelers_In_DC — Tue, 08 Dec 2015 18:27:31 GMT

I was hoping someone else answered so I can see the solution. I'm not the best person to answer this question but see if this gets the desired results, with the test data it works:

data want;
length acctnum 8. promisedate 8. promiseamt 8. bwindow 8. ewindow 8.;
if _N_ = 1 then do;
   declare hash e(dataset:'promise');
   e.definekey('acctnum');
   e.definedata('promisedate','promiseamt','bwindow','ewindow');
   e.definedone();
end;
set Payments;
drop rc;
rc = e.find();
if rc = 0 and bwindow <= paydate <= ewindow;
format promisedate bwindow ewindow mmddyy10.;
run;

Re: Hash Question

redfishJAX — Thu, 10 Dec 2015 15:48:36 GMT

Thanks for your help.

I will give this a try and see how it works.