topic Re: Array Loop Help in SAS Programming

Array Loop Help

Jsendzik — Mon, 17 Feb 2014 20:30:27 GMT

Hey,

I'm trying to write a loop that will give me the count of zero's after a provided input variable. I keep getting an error when I try to write it. Any help would be much appreciated.

day1	day2	day3	day4	day5	Start
1	1	1	1	0	1
0	1	0	0	1	2
1	1	1	0	0	3

This is what I envision the loop to look like, but its not working.

data array_loop;

set in_data;

array test(*) day1-day5;

do i = 0 to (5 - start);

if test(start + i ) = 0 then counter +1;

end;

run;

Re: Array Loop Help

PGStats — Mon, 17 Feb 2014 20:51:55 GMT

Try this:

data array_loop;

set in_data;

array test{*} day1-day5;

counter = 0;

do i = start to dim(test);

counter = counter + test{i}=0;

end;

drop i;

run;

Re: Array Loop Help

Tom — Mon, 17 Feb 2014 20:56:51 GMT

Looks like its working to me.

data array_loop;

set in_data;

array test(*) day1-day5;

do i = 0 to (5 - start);

if test(start + i ) = 0 then counter +1;

end;

put (day1-day5 start counter) (:);

run;

1 1 1 1 0 1 1

0 1 0 0 1 2 3

1 1 1 0 0 3 5

Now because you are retaining your counter variable each new rows starts counting at the value retained from the previous row.

Did you want it to count each row separately? Just at counter=0 before the DO loop.

Re: Array Loop Help

overmar — Mon, 17 Feb 2014 21:10:14 GMT

It may also make sense to use this:

do i = 0 to (dim(test)-start);

Instead of the 5-start so you don't have to count the number of rows, the inherent reason why you use (*) rather than putting a 5 into the array statement.