topic Re: Conditionally loop dependent on prior observation in SAS Programming

Conditionally loop dependent on prior observation

adschiltz — Fri, 13 May 2022 13:26:51 GMT

Having some programming issues. I would like to take a table that has information populated for the first ID, and populate the rest of the observations for the ID according to specific conditions.

1. I would like to populate REV_DATE_LAST with the most recent REV_DATE_LAST by ID, unless the prior observation included Mark=1.

2. I would then like to calculate REV_AGE as YEARMO - REV_DATE_LAST.

3. Mark should =1 if REV_AGE is GE 12 unless FLAG=1

The intent is to review each ID every 12 months, unless they are flagged, then the review should take place once they are no longer flagged.

I have tried many different potential solutions with no avail including lags, retains, counts, etc.

HAVE:

ID	YEARMO	REV_DATE_LAST	FLAG	REV_AGE	MARK
1	201803	201608		22	1
1	201804
1	201805
1	201806
1	201807
1	201808
1	201809
1	201810
1	201811
1	201812
1	201901
1	201902
1	201903
1	201904
1	201905
1	201906
2	201803	201607	1	21
2	201804		1
2	201805		1
2	201806		1
2	201807		1
2	201808		1
2	201809		1
2	201810		1
2	201811		1
2	201812		1
2	201901		1
2	201902		1
2	201903
2	201904
2	201905
2	201906		1
2	201907		1
2	201908		1
2	201909		1
2	201910		1
2	201911		1
2	201912		1
2	202001		1
2	202002		1
2	202003
2	202004
2	202005

WANT:

ID	YEARMO	REV_DATE_LAST	FLAG	REV_AGE	MARK
1	201803	201608		22	1
1	201804	201804		0	.
1	201805	201804		1	.
1	201806	201804		2	.
1	201807	201804		3	.
1	201808	201804		4	.
1	201809	201804		5	.
1	201810	201804		6	.
1	201811	201804		7	.
1	201812	201804		8	.
1	201901	201804		9	.
1	201902	201804		10	.
1	201903	201804		11	.
1	201904	201804		12	1
1	201905	201905		0	.
1	201906	201905		1	.
2	201803	201607	1	21	.
2	201804	201607	1	22	.
2	201805	201607	1	23	.
2	201806	201607	1	24	.
2	201807	201607	1	25	.
2	201808	201607	1	26	.
2	201809	201607	1	27	.
2	201810	201607	1	28	.
2	201811	201607	1	29	.
2	201812	201607	1	30	.
2	201901	201607	1	31	.
2	201902	201607	1	32	.
2	201903	201607		33	1
2	201904	201904		0	.
2	201905	201904		1	.
2	201906	201904	1	2	.
2	201907	201904	1	3	.
2	201908	201904	1	4	.
2	201909	201904	1	5	.
2	201910	201904	1	6	.
2	201911	201904	1	7	.
2	201912	201904	1	8	.
2	202001	201904	1	9	.
2	202002	201904	1	10	.
2	202003	201904		11	.
2	202004	201904		12	1
2	202005	202005		0

Re: Conditionally loop dependent on prior observation

Kurt_Bremser — Fri, 13 May 2022 14:20:33 GMT

Your initial rev_age values for both groups are wrong, given the values of yearmo and rev_date_last.

But see this code:

data have;
infile datalines dlm="09"x dsd truncover;
input ID YEARMO :yymmn6. REV_DATE_LAST :yymmn6. FLAG REV_AGE MARK;
format yearmo rev_date_last yymmn6.;
datalines;
1	201803	201608	 	22	1
1	201804	 	 	 	 
1	201805	 	 	 	 
1	201806	 	 	 	 
1	201807	 	 	 	 
1	201808	 	 	 	 
1	201809	 	 	 	 
1	201810	 	 	 	 
1	201811	 	 	 	 
1	201812	 	 	 	 
1	201901	 	 	 	 
1	201902	 	 	 	 
1	201903	 	 	 	 
1	201904	 	 	 	 
1	201905	 	 	 	 
1	201906	 	 	 	 
2	201803	201607	1	21	 
2	201804	 	1	 	 
2	201805	 	1	 	 
2	201806	 	1	 	 
2	201807	 	1	 	 
2	201808	 	1	 	 
2	201809	 	1	 	 
2	201810	 	1	 	 
2	201811	 	1	 	 
2	201812	 	1	 	 
2	201901	 	1	 	 
2	201902	 	1	 	 
2	201903	 	 	 	 
2	201904	 	 	 	 
2	201905	 	 	 	 
2	201906	 	1	 	 
2	201907	 	1	 	 
2	201908	 	1	 	 
2	201909	 	1	 	 
2	201910	 	1	 	 
2	201911	 	1	 	 
2	201912	 	1	 	 
2	202001	 	1	 	 
2	202002	 	1	 	 
2	202003	 	 	 	 
2	202004	 	 	 	 
2	202005	 	 	 	 
;

data want;
set have (rename=(rev_date_last=_rev_date_last mark=_mark));
by id;
retain rev_date_last mark;
format rev_date_last yymmn6.;
if first.id
then do;
  rev_date_last = _rev_date_last;
  mark = _mark;
end;
else do;
  if mark 
  then do;
    rev_date_last = yearmo;
    mark = .;
  end;
end;
rev_age = intck('month',rev_date_last,yearmo);
if not flag and rev_age ge 12 then mark = 1;
drop _:;
run;

Re: Conditionally loop dependent on prior observation

adschiltz — Fri, 13 May 2022 15:19:32 GMT

Kurt,

Brilliant solution. Thank you for posting! Have a great weekend.

- adschiltz