topic Variables in macro in SAS Programming

Variables in macro

natmaks — Thu, 15 Nov 2012 14:23:32 GMT

I am trying to write my first macro and I am having problems manipulating the parameters inside macro. This is the code:

%macro SecondDerivative_New (parlambda, parepsilon);

m=%sysevalf(&parlambda+&parepsilon); /* this gives an error ERROR: A character operand was found in the %EVAL function or %IF condition where a numeric operand is required. The condition was: lambda+epsilon */

result1=%FirstDerivative(parlambda=m);

%mend;

%macro FirstDerivative (parlambda=);

10/&parlambda+24*(exp(-1*&parlambda))/(1-exp(-1*&parlambda))-28.52;

%mend;

/* call macro */

data;

lambda=0.799;

epsilon=0.001;

%SecondDerivative_New(lambda,epsilon);

Thank you

Re: Variables in macro

PaigeMiller — Thu, 15 Nov 2012 14:29:58 GMT

I assume that you have greatly simplified things from a much more complex situation.

Based on what you have shown, macros are completely unnecessary here, but maybe they are needed in a more complex situation...

You cannot add data set variables using %SYSEVALF. You can only add macro variables using %SYSEVALF.

So, &parlambda resolves to lambda (which is not a macro variable, it is a datastep variable). &parepsilon resolves to epsilon (which is not a macro variable, it is a datastep variable).

If your macro is always going to have arguments that resolve to datastep variables, then you simply say

m=&parlambda + &parepsilon;

But as I said, using macros and macro variables in this simple situation is completely unnecessary.

Re: Variables in macro

natmaks — Thu, 15 Nov 2012 14:41:01 GMT

thank you. Yes, it is just a simplified piece.