topic Concatenate Value Based on Header Name in SAS Programming

Concatenate Value Based on Header Name

cobba — Sun, 12 Dec 2021 22:34:40 GMT

I have the following data. The real data is about 100 columns

data have;
    input id$ cause1$ cause2$ cause3$ effect1$ effect2$ effect3$ @@@@@@@;
    datalines;
    aa 001 001 002 001 003 .
    bb 005 . . 004 005 001
    cc 001 003 002 001 003 002
    dd 002 004 009 002 005 006
    ;
run;

The codes aren't very helpful for analysis. So I'd like to add a character to the start based on the header.

Re: Concatenate Value Based on Header Name

Reeza — Mon, 13 Dec 2021 00:06:15 GMT

VNAME function within an array.

data want;
set have;

array _vars(*) cause1--effect3;

do i=1 to dim(_vars);
     _vars(i) = catt(substr(vname(_vars), 1, 1), _vars(i));
end;

run;

@cobba wrote:

I have the following data. The real data is about 100 columns
data have;
    input id$ cause1$ cause2$ cause3$ effect1$ effect2$ effect3$ @@@@@@@;
    datalines;
    aa 001 001 002 001 003 .
    bb 005 . . 004 005 001
    cc 001 003 002 001 003 002
    dd 002 004 009 002 005 006
    ;
run;
The codes aren't very helpful for analysis. So I'd like to add a character to the start based on the header.

Re: Concatenate Value Based on Header Name

cobba — Mon, 13 Dec 2021 00:25:55 GMT

I'm getting the following error when I run your code. I am running SAS EG 7.1 under SAS v9.3

ERROR: Array subscript out of range at line 39 column 30.
id=aa cause1=001 cause2=001 cause3=002 effect1=001 effect2=003 effect3= i=1 _ERROR_=1 _N_=1

Re: Concatenate Value Based on Header Name

Shmuel — Mon, 13 Dec 2021 00:35:48 GMT

Replace line:

 _vars(i) = catt(substr(vname(_vars), 1, 1), _vars(i));

into:

 _vars(i) = catt(substr(vname(_vars(i)), 1, 1), _vars(i));

Re: Concatenate Value Based on Header Name

Reeza — Mon, 13 Dec 2021 01:04:20 GMT

Replace the IF with this:

Accounts for missing and I had missed the (i) in the array reference within the VNAME() function.

if not missing(_vars(i)) then _vars(i) = catt(substr(vname(_vars(i)), 1, 1), _vars(i));