topic Re: Dynamically Finding the 28th of Each Month in SAS Programming

Dynamically Finding the 28th of Each Month

Jeff_DOC — Mon, 15 Mar 2021 22:39:07 GMT

Good afternoon.

I would appreciate any help someone could offer.

Basically I need to have an older program run for data for the 28th day of each month on the first of the subsequent month. So on May 1 the beginmonth variable needs to allow me to run for data from March 28th to April 28th. I can do the report programming piece but what I can't get correct is to shift the date each month to the correct 28th day.

Here's the old section that will create the variables as they were before. I need to change these to find the 28th of each month, not the beginning or end of the time period as shown.

Any help would be greatly appreciated.

data params;
attrib
run_date length=8 format = mmddyy10.
beginmonth length=8 format = mmddyy10.
endingmonth length=8 format = mmddyy10.
rep_start_date length=$10
rep_end_date length=$10;

today = put(date(),worddate18.);

run_date = today();
beginmonth=intnx('month',run_date,-2, "BEGIN");
endingmonth=intnx('month',run_date,-1, "END");
rep_start_date=put(beginmonth, mmddyy10.);
rep_end_date=put(endingmonth, mmddyy10.);

call symput("run_date",run_date);
call symput("beginmonth",beginmonth);
call symput("endingmonth",endingmonth);
call symput("rep_start_date",rep_start_date);
call symput("rep_end_date",rep_end_date);
call symput('today',today);
run;

Re: Dynamically Finding the 28th of Each Month

ballardw — Mon, 15 Mar 2021 22:43:52 GMT

Here's one way to find the 28th of the month preceding any date:

data example;
   date = today();
   prior28 = intnx('month',date,-1,'B') + 27;
   put date= date9. prior28= date9.;
run;

The B is the beginning so add 27 to get to 28 since date values are integer numbers of days.

Re: Dynamically Finding the 28th of Each Month

Reeza — Mon, 15 Mar 2021 22:55:17 GMT

Which macro variables do you need to change?
What do you need them to change to?
Have you looked at the "S" option for alignment of parameter?
You're aware you can add 27 to the start of a month to get the 28th date?
Want the 28th for the previous month? That would be the start of the previous month + 27.

data params;

start_date = '01May2021'd;


*run_date = today();
run_date = start_date;

beginmonth=intnx('month',run_date,-2, "B");
endingmonth=intnx('month',run_date,-1, "B");
rep_start_date=put(beginmonth+27, mmddyy10.);
rep_end_date=put(endingmonth+27, mmddyy10.);


run;

proc print data=params;
run;


Obs	start_date	run_date	beginmonth	endingmonth	rep_start_date	rep_end_date
1	22401	22401	22340	22371	03/28/2021	04/28/2021

@Jeff_DOC wrote:

Good afternoon.

I would appreciate any help someone could offer.

Basically I need to have an older program run for data for the 28th day of each month on the first of the subsequent month. So on May 1 the beginmonth variable needs to allow me to run for data from March 28th to April 28th. I can do the report programming piece but what I can't get correct is to shift the date each month to the correct 28th day.

Here's the old section that will create the variables as they were before. I need to change these to find the 28th of each month, not the beginning or end of the time period as shown.

Any help would be greatly appreciated.

data params;
attrib
run_date length=8 format = mmddyy10.
beginmonth length=8 format = mmddyy10.
endingmonth length=8 format = mmddyy10.
rep_start_date length=$10
rep_end_date length=$10;

today = put(date(),worddate18.);

run_date = today();
beginmonth=intnx('month',run_date,-2, "BEGIN");
endingmonth=intnx('month',run_date,-1, "END");
rep_start_date=put(beginmonth, mmddyy10.);
rep_end_date=put(endingmonth, mmddyy10.);

call symput("run_date",run_date);
call symput("beginmonth",beginmonth);
call symput("endingmonth",endingmonth);
call symput("rep_start_date",rep_start_date);
call symput("rep_end_date",rep_end_date);
call symput('today',today);
run;

Re: Dynamically Finding the 28th of Each Month

Jeff_DOC — Mon, 15 Mar 2021 23:27:50 GMT

Since you both gave me a correct answer I flipped a coin (yes, I'm old enough to still carry coins) and Ballardw won!

Thanks to you both for being willing to help!

Re: Dynamically Finding the 28th of Each Month

Jeff_DOC — Mon, 15 Mar 2021 23:31:05 GMT

Since you both gave me a correct answer I flipped a coin (yes, I'm old enough to still carry coins) and Ballardw won!

Thanks for being willing to help!