topic Re: Date extract in SAS Programming

Date extract

Sowmya12 — Tue, 23 Feb 2021 11:43:40 GMT

If date is 2019/un/un.how can I get 2019 or 11/un/un.from this how we can extract 11

Re: Date extract

Kurt_Bremser — Tue, 23 Feb 2021 11:52:58 GMT

11 is not a year (2011 would be).

If you don't even know the order of the parts (YMD, DMY or MDY), you can't solve this.

Re: Date extract

Amir — Tue, 23 Feb 2021 12:07:22 GMT

Hi @Sowmya12,

If the first part of your data is always the year, then the below might help (assuming your date is character, based on what you've shown).

The scan() function selects part of string that is separated by a specific character(s).

data have;
   input my_date : $char10.;

   datalines;
2019/un/un
11/un/un
;


data want;
   set have;
   
   y = scan(my_date,1,'/');
run;

Kind regards,

Amir.

Re: Date extract

Amir — Tue, 23 Feb 2021 12:15:21 GMT

Hi @Sowmya12,

I meant to add a length statement to give y a length of 4.

Kind regards,

Amir.

Re: Date extract

Kurt_Bremser — Tue, 23 Feb 2021 12:18:31 GMT

I would store year as a number with length 3. This allows years up to 8192, consumes the least space, and can be used in calculations or functions without conversion.

Re: Date extract

Amir — Tue, 23 Feb 2021 12:42:18 GMT

True.