topic Re: proc template with layout gridded in SAS Programming

proc template with layout gridded

unnati — Thu, 24 Dec 2020 16:18:23 GMT

Hello All,

In following code I am trying to resolve ZVAR(age)value directly from dataset just the way I am able
to do XVAR and YVAR by using them in dynamic statement.

Can someone help me to understand why ZVAR is not resolve from entry halign

proc template;
  define statgraph regfit;
    dynamic XVAR YVAR ZVAR;
    mvar STUDY SYSDATE sex;
    begingraph;
      entrytitle "Scatter plot of " YVAR " = " XVAR;
      entryfootnote halign=left STUDY halign=right SYSDATE;
      layout overlay;
        scatterplot X=XVAR Y=YVAR;
layout gridded / opaque=true backgroundcolor=CXECECEC border=false rows=4 columns=2 border=false autoalign=(topright topleft bottomright bottomleft);

						/*- Line 1-2 -*/
						entry halign=left "subject gender=zvar" ;
						entry halign=left zvar;
					endlayout;
      endlayout;
    endgraph;
  end;
run;

%let study=CLASS dataset;
proc sgrender data=sashelp.class template=regfit;
  dynamic xvar="height" yvar="weight" zvar="age";
  where name='Alfred';
run;

Thank you.

Re: proc template with layout gridded

ballardw — Thu, 31 Dec 2020 20:51:50 GMT

It would help if show what you expect or want to appear in the Entry result in the graph.

Any text in quotes is going to be literal.

So when you use

entry halign=left "subject gender=zvar" ;

That is exactly what you get.

The combination of that line an the next:

entry halign=left "subject gender=zvar" ;
entry halign=left zvar;

uses the resolved value of ZVAR to create

"subject gender=zvar age"

because the resolved text of zvar is "age"

I can't really go much further as I have no clue what you are actually attempting to place into the entry.

Re: proc template with layout gridded

unnati — Mon, 04 Jan 2021 17:41:32 GMT

I am trying to resolve value for age. For example subject age is 29 then i want that ZVAR to resolved into "29".