Arrays with if.first then

seancho — Sat, 17 Oct 2020 09:14:34 GMT

Hello all,

Instead of writing multiple lines on DATA population2 step, I am trying to use arrays. However, I receive message; "Missing numeric suffix on a numbered variable list"

Could you please help? Thank you in advance!

DATA population2;
	SET population;

	by state_2;

	if first.state_2 then cum_1990 = _1990;
	else cum_1990 + _1990;
	if last.state_2 then output;

RUN;


DATA population3;
	SET population;

	by State_2;

	array year_array {30} _1990 - _2019;
	array cum_array {30} _1990cum - _2019cum;

	do i = 1 to 30;
		if first.state_2 then cum_array {i} = year_array {i} ;
		else cum_array {i} + year_array{i};
		if last.state_2 then output;

	end;
RUN;

Re: Arrays with if.first then

Kurt_Bremser — Sat, 17 Oct 2020 09:21:16 GMT

On a numbered variable list, the numeric suffix has to be at the end of the variable name:

array cum_array {30} _cum1990 - _cum2019;

topic Arrays with if.first then in SAS Programming

Arrays with if.first then

Re: Arrays with if.first then