topic Re: Data Step in SAS Programming

Data Step

jacksonan123 — Fri, 11 Oct 2019 13:46:21 GMT

I get the following error with the code:

ERROR 124-185 when macro with array is invoked more than once in DATA step. I have read the post but I don't quite understand how it applies to my code. The specific log is:

[90 array subn(*) subn1-subn34;

____

124

ERROR 124-185: The variable subn has already been defined.

91 do i=1 to 34;

92 SUBJ(i)=1/(1+exp(-subn(i)));

____

ERROR 68-185: The function SUBN is unknown, or cannot be accessed.]

I need to know how to interpret and correct the error in my code since data test2 will not run but test1 runs just fine?

data test;
input   param $  sub1  treat $ subn  ;
cards;
logit -1.11 ates -0.03
logit -1.11 bref -0.03 
ka2 -0.50  bref -0.01
ka2 -0.50 ates -0.01
;
run;


data test1;
set test;
if Param in(  'logit' );
array subj(*) subj1-subj34;
array sub(*) sub1-sub34;
do i=1 to 34;
subj(i)=1/(1+exp(-sub(i)));

end;
run;
RUN;

data test2;
set test;
if Param in(  'logit' );
array subj(*) subj1-subj34;
array subn(*) subn1-subn34;
do i=1 to 34;
SUBJ(i)=1/(1+exp(-subn(i)));
end;
run;
RUN;

Re: Data Step

novinosrin — Fri, 11 Oct 2019 13:52:42 GMT

Hi @jacksonan123 You have a variable in your Input dataset named SUBN. Therefore that causes a conflict with your 2nd array name at compile time in TEST2

5655  data test2;
5656  set test;
5657  if Param in(  'logit' );
5658  array subj(*) subj1-subj34;
5659  array subn(*) subn1-subn34;run;
            ----
            124

ERROR 124-185: The variable subn has already been defined.

Please choose a different array name.

Re: Data Step

jacksonan123 — Fri, 11 Oct 2019 14:11:32 GMT

I have tried that in the past and I changed it to:

Data test2;

Set test;

..

Array subx(*) subx1-subx34;

..

Subj(i)=1/(1+exp(-subx(i)));

But my answer is

Test 1

Param sub1 treat subn subj1

Logit -1.11 ates -0.03 0.24

Test2

Param sub1 treat subn subj1

Logit -1.11 ates -0.03 .

The test2 should have the result from the calculation
Subj(i)=1/(1+exp(-subx(i)));

However I get a (.) for subj1 (i.e., no calculation value missing), but the
same code does give the correct answer for Test1.

That is what I need to know why so Test2 can be corrected.

Re: Data Step

Kurt_Bremser — Fri, 11 Oct 2019 14:46:50 GMT

Since you do not have a variable subn1 (or subx1) in your input dataset, the array consists entirely of missing values.