topic Re: Arrays - How to compare columns, then output indicator? in SAS Programming

Arrays - How to compare columns, then output indicator?

Gpp — Mon, 03 Jun 2019 14:41:45 GMT

Hi all, I am really bad in array, hoping someone can help me to complete the array.

I have to compare column1 vs column2, then column2 vs column3... and each comparison I want create a indicator field.

dataset A is the table that I want to compare.

dataset B is the incomplete code that I try to write, I know my array c{*} is incorrect but I don't know how to modify it.

Sample output of dataset D, the last 5 columns in numeric are what I want to compute.

%let mthrun=5;
%let dt=01mar2019;

data _null_;
	do i=1 to &mthrun.;
	mth=put(intnx('month', "&dt"d, i-&mthrun.),yymmn6.);
	call symput ("mth"||compress(i),mth);
	put i mth;
	end;
run;

data A;
input id $2. J_201811 $2.  J_201812 $2.  J_201901 $2.  J_201902 $2.  J_201903 $2.;
DATALINES;
AAQ1Q1Q1Q3T5
BB  R1Q1R1T1
CC    Y1Y1Y1
DDG1G1G1G1G1
;
run;


DATA B;
	SET A;
	ARRAY JC{*} J_:;
	ARRAY C{*} C_J:;
		DO i=1 to dim(JC)-1;
		IF jc{i} NE "" AND jc{i} NE jc{i+1} THEN C_J{i+1}=1;
			else C_J{i+1}=0;
		END; 
RUN;

DATA D;
	SET A;
	IF J_201811 NE '' AND J_201811 NE J_201812 THEN C_J_201812=1; ELSE C_J_201812=0;
	IF J_201812 NE '' AND J_201812 NE J_201901 THEN C_J_201901=1; ELSE C_J_201901=0;
	IF J_201901 NE '' AND J_201901 NE J_201902 THEN C_J_201902=1; ELSE C_J_201902=0;
	IF J_201902 NE '' AND J_201902 NE J_201903 THEN C_J_201903=1; ELSE C_J_201903=0;
	NO_OF_CHANGES=SUM(OF C_J_201812--C_J_201903);
RUN;

Thank you in advance 😃

Re: Arrays - How to compare columns, then output indicator?

Reeza — Mon, 03 Jun 2019 15:04:15 GMT

It may help if you explain what you're trying to do overall. I would recommend redesigning this approach to work with a long data set and then flip at the end for reporting. It's more dynamic that way and you are less likely to need to hardcode any values.

@Gpp wrote:

Hi all, I am really bad in array, hoping someone can help me to complete the array.

I have to compare column1 vs column2, then column2 vs column3... and each comparison I want create a indicator field.

dataset A is the table that I want to compare.

dataset B is the incomplete code that I try to write, I know my array c{*} is incorrect but I don't know how to modify it.

Sample output of dataset D, the last 5 columns in numeric are what I want to compute.
%let mthrun=5;
%let dt=01mar2019;

data _null_;
	do i=1 to &mthrun.;
	mth=put(intnx('month', "&dt"d, i-&mthrun.),yymmn6.);
	call symput ("mth"||compress(i),mth);
	put i mth;
	end;
run;

data A;
input id $2. J_201811 $2.  J_201812 $2.  J_201901 $2.  J_201902 $2.  J_201903 $2.;
DATALINES;
AAQ1Q1Q1Q3T5
BB  R1Q1R1T1
CC    Y1Y1Y1
DDG1G1G1G1G1
;
run;


DATA B;
	SET A;
	ARRAY JC{*} J_:;
	ARRAY C{*} C_J:;
		DO i=1 to dim(JC)-1;
		IF jc{i} NE "" AND jc{i} NE jc{i+1} THEN C_J{i+1}=1;
			else C_J{i+1}=0;
		END; 
RUN;

DATA D;
	SET A;
	IF J_201811 NE '' AND J_201811 NE J_201812 THEN C_J_201812=1; ELSE C_J_201812=0;
	IF J_201812 NE '' AND J_201812 NE J_201901 THEN C_J_201901=1; ELSE C_J_201901=0;
	IF J_201901 NE '' AND J_201901 NE J_201902 THEN C_J_201902=1; ELSE C_J_201902=0;
	IF J_201902 NE '' AND J_201902 NE J_201903 THEN C_J_201903=1; ELSE C_J_201903=0;
	NO_OF_CHANGES=SUM(OF C_J_201812--C_J_201903);
RUN;
Thank you in advance 😃

Re: Arrays - How to compare columns, then output indicator?

Gpp — Mon, 03 Jun 2019 15:16:34 GMT

Hello Reza, I am trying to know for the past 2 years (24 column for each month ) any changes between previous month and current month.

Example j_201811=“Q1” and j_201812=“W1” then count=1.
But if the j_201811 = “” and j_201812 ne “”, then is not consider as a change , so count=0
j_201811=“Q1” and j_201812=“Q1” then count=0

in the end of the day I want to know , how many times the contents of the column changed.

Re: Arrays - How to compare columns, then output indicator?

Reeza — Mon, 03 Jun 2019 15:27:53 GMT

Your code seems mostly correct to me then, what isn't happening that you want to happen.

I can't run your code because you didn't provide any sample data (image is not data).

Re: Arrays - How to compare columns, then output indicator?

Gpp — Mon, 03 Jun 2019 15:31:50 GMT

%let mthrun=5;
%let dt=01mar2019;

data _null_;
do i=1 to &mthrun.;
mth=put(intnx('month', "&dt"d, i-&mthrun.),yymmn6.);
call symput ("mth"||compress(i),mth);
put i mth;
end;
run;

data A;
input id $2. J_201811 $2. J_201812 $2. J_201901 $2. J_201902 $2. J_201903 $2.;
DATALINES;
AAQ1Q1Q1Q3T5
BB R1Q1R1T1
CC Y1Y1Y1
DDG1G1G1G1G1
;
run;

DATA B;
SET A;
ARRAY JC{*} J_:;
ARRAY C{*} C_J:;
DO i=1 to dim(JC)-1;
IF jc{i} NE "" AND jc{i} NE jc{i+1} THEN C_J{i+1}=1;
else C_J{i+1}=0;
END;
RUN;

DATA D;
SET A;
IF J_201811 NE '' AND J_201811 NE J_201812 THEN C_J_201812=1; ELSE C_J_201812=0;
IF J_201812 NE '' AND J_201812 NE J_201901 THEN C_J_201901=1; ELSE C_J_201901=0;
IF J_201901 NE '' AND J_201901 NE J_201902 THEN C_J_201902=1; ELSE C_J_201902=0;
IF J_201902 NE '' AND J_201902 NE J_201903 THEN C_J_201903=1; ELSE C_J_201903=0;
NO_OF_CHANGES=SUM(OF C_J_201812--C_J_201903);
RUN;

Can you use this ? Dataset A is my sample data . Dataset b is my desired output

Re: Arrays - How to compare columns, then output indicator?

Reeza — Mon, 03 Jun 2019 15:35:26 GMT

If B is expected output, what's wrong with the code?
If B is close but not exact, please show an exact output expected.

Re: Arrays - How to compare columns, then output indicator?

Gpp — Mon, 03 Jun 2019 15:40:00 GMT

Sorry, is D will generate the output that I want , but D is too lengthy , so I try to use array in B, but B with error. I am not sure how to make B correct

Re: Arrays - How to compare columns, then output indicator?

Reeza — Mon, 03 Jun 2019 15:55:22 GMT

You can't declare an array like this when it doesn't exist. This type of function only works when you have the variables already in the data set:

ARRAY C{*} C_J:;

So you need to explicitly list the elements out and it will work fine.

That being said, that's why this is not a dynamic solution - it becomes hard coded and requires you modifying it every month or every run. Changing it to a long format doesn't require any of these issues and simplifies your code massively.

Re: Arrays - How to compare columns, then output indicator?

Reeza — Mon, 03 Jun 2019 16:17:44 GMT

This is how I would approach this instead:



data A;
input id $2. J_201811 $2. J_201812 $2. J_201901 $2. J_201902 $2. J_201903 $2.;
DATALINES;
AAQ1Q1Q1Q3T5
BB R1Q1R1T1
CC Y1Y1Y1
DDG1G1G1G1G1
;
run;

*transpose to a long format;
proc transpose data=A out=long1;
by ID;
VAR J:;
run;

*add in dates and rename columns;
data long2;
set long;
date = input(substr(_name_, 3, 6), yymmn6.);
format date yymmn6.;
rename col1 = VALUE;
drop _name_ ;
run;

*check if matches previous value;
data long3;
set long2;
by ID date;

*gets previous value;

prev_value = lag(value);

*checks if new id and sets to missing if it is a new ID;
if first.id then call missing(prev_value);

*code as 1/0 if the same as previous value;
if not first.id then do;
if prev_value = value then flag=1; else flag=0;
end;

run;

*calculate summary statistics;
proc sql;
create table comparison as
select ID, mean(flag) as Percent_Change format=percent12.1, sum(flag) as N_Changed, n(flag) as N_Records
from long3
group by ID;
quit;

Re: Arrays - How to compare columns, then output indicator?

Gpp — Mon, 03 Jun 2019 16:21:10 GMT

Thank you so much for spending time for my question. I will definitely try your method.

Just an additional question on array , how to explicitly list the element? Is it Array c[*] $; ? Thanks again!

Re: Arrays - How to compare columns, then output indicator?

Reeza — Mon, 03 Jun 2019 16:24:18 GMT

array c(*) $ C_201811 C_201812 C_201901 ....  C_201912;

You have to list all the elements individually if you need new elements with a different prefix. You could automate that portion with a macro variable or macro as well.

@Gpp wrote:
Thank you so much for spending time for my question. I will definitely try your method.

Just an additional question on array , how to explicitly list the element? Is it Array c[*] $; ? Thanks again!