topic Re: Reformatting short to long date data for survival analysis in SAS Programming

Reformatting short to long date data for survival analysis

ammarhm — Wed, 29 May 2019 13:22:19 GMT

Hi everyone,

I have a question regarding changing short to long data frame and splitting dates.

Here is the initial data frame:

Patient	Initials	age	Entry	Exit	Event1	Event2	Weight
K89R	AB	34	27-Jul-10	17-Aug-13	1-Mar-08	2-May-11	44
S33T	ES	55	23-Jul-09	12-Mar-12	17-Sep-10	.	76

What you see here, is that there is an entry and exit dates, with dates for the events 1 and 2, there is also a missing date for event 2 for the second patient because the event didn't happen. Also note that the event1 for the first patient happened before entry date.

What I want to get is the following file:

Patient	Initials	age	Entry	Exit	Event1	Event2	Weight
K89R	AB	34	27/07/2010	31/12/2010	1	0	44
K89R	AB	34	1/01/2011	31/12/2011	1	1	44
K89R	AB	34	1/01/2012	31/12/2012	1	1	44
K89R	AB	34	1/01/2013	17/08/2013	1	1	44
S33T	ES	55	23/07/2009	31/12/2009	0	0	76
S33T	ES	55	1/01/2010	31/12/2010	1	0	76
S33T	ES	55	1/01/2011	31/12/2011	1	0	76
S33T	ES	55	1/01/2012	12/03/2012	1	0	76

What you notice here is that the entry to exit date period is split into individual rows per patient, each representing a year. The event columns are now coded as 0 (meaning the event has not yet happened) or 1 (the event happened) which is then carried over to the years after because the event has already happened.

The age increases in every row per patient as time progresses

The patient ID and initial remain the same as well as the weight.

Could anyone please help with this, thank you

Re: Reformatting short to long date data for survival analysis

Kurt_Bremser — Wed, 29 May 2019 14:34:54 GMT

Solved with a do until and using the intnx() function:

data have;
input patient :$4. entry :yymmdd10. exit :yymmdd10. event1 :yymmdd10. event2 :yymmdd10.;
format entry exit event1 event2 yymmddd10.;
datalines;
K98R 2010-07-27 2013-08-17 2008-03-01 2011-05-02
S33T 2009-07-23 2012-03-12 2010-09-17 .
;

data want;
set have (rename=(exit=_exit event1=_event1 event2=_event2));
format exit yymmddd10.;
exit = min(intnx('year',entry,0,'e'),_exit);
do until (exit = _exit);
  if _event1 ne . and _event1 <= exit then event1 = 1; else event1 = 0;
  if _event2 ne . and _event2 <= exit then event2 = 1; else event2 = 0;
  output;
  entry = intnx('year',entry,1,'b');
  exit = min(intnx('year',exit,1,'e'),_exit);
end;
output;
keep patient entry exit event1 event2;
run;

proc print data=want noobs;
run;

Result:

patient         entry          exit    event1    event2

 K98R      2010-07-27    2010-12-31       1         0  
 K98R      2011-01-01    2011-12-31       1         1  
 K98R      2012-01-01    2012-12-31       1         1  
 K98R      2013-01-01    2013-08-17       1         1  
 S33T      2009-07-23    2009-12-31       0         0  
 S33T      2010-01-01    2010-12-31       1         0  
 S33T      2011-01-01    2011-12-31       1         0  
 S33T      2012-01-01    2012-03-12       1         0

Re: Reformatting short to long date data for survival analysis

Ksharp — Thu, 30 May 2019 13:24:26 GMT

data have;
input patient :$4. entry :yymmdd10. exit :yymmdd10. event1 :yymmdd10. event2 :yymmdd10.;
format entry exit event1 event2 yymmdd10.;
datalines;
K98R 2010-07-27 2013-08-17 2008-03-01 2011-05-02
S33T 2009-07-23 2012-03-12 2010-09-17 .
;
data temp;
 set have;
 id+1;
 do date=entry to exit;
  year=year(date);
  flag1=(date>=event1 and not missing(event1));
  flag2=(date>=event2 and not missing(event2));
  output;
 end;
run;
proc sql;
create table want as
 select id,patient,min(date) as entry format=yymmdd10.,
 max(date) as exit format=yymmdd10.,
 max(flag1) as event1,
 max(flag2) as event2
  from temp
   group by id,patient,year;
quit;

Re: Reformatting short to long date data for survival analysis

ammarhm — Thu, 30 May 2019 14:10:58 GMT

Thank you @Ksharp and @Kurt_Bremser

Both solutions work like a charm.