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    <title>topic Re: SAS intnx function query in SAS Programming</title>
    <link>https://communities.sas.com/t5/SAS-Programming/SAS-intnx-function-query/m-p/536528#M147443</link>
    <description>&lt;P&gt;Once you have this much:&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;P&gt;%LET RUNDATE = TODAY();&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;P&gt;data&amp;nbsp; _null_;&lt;BR /&gt;call symput("A",put(intnx('YEAR',&amp;amp;RUNDATE,-1),YEAR4.));&lt;BR /&gt;run;&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;P&gt;That lets you continue with:&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;P&gt;%let B = %eval(&amp;amp;A + 1);&lt;/P&gt;
&lt;P&gt;%let C = &amp;amp;A/&amp;amp;B;&lt;/P&gt;</description>
    <pubDate>Mon, 18 Feb 2019 16:55:02 GMT</pubDate>
    <dc:creator>Astounding</dc:creator>
    <dc:date>2019-02-18T16:55:02Z</dc:date>
    <item>
      <title>SAS intnx function query</title>
      <link>https://communities.sas.com/t5/SAS-Programming/SAS-intnx-function-query/m-p/536413#M147412</link>
      <description>&lt;P&gt;In the below code, I can get 2018 for variable A and 2019 for variable B.&amp;nbsp; May I know how to get 2018/2019 for variable C? Thanks.&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;%LET RUNDATE = TODAY();&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;data&amp;nbsp; _null_;&lt;BR /&gt;call symput("A",put(intnx('YEAR',&amp;amp;RUNDATE,-1),YEAR4.));&lt;BR /&gt;call symput("B",put(intnx('YEAR',&amp;amp;RUNDATE,0),YEAR4.));&lt;BR /&gt;run;&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;%PUT A = &amp;amp;A;&lt;BR /&gt;%PUT B = &amp;amp;B;&lt;/P&gt;</description>
      <pubDate>Mon, 18 Feb 2019 09:33:49 GMT</pubDate>
      <guid>https://communities.sas.com/t5/SAS-Programming/SAS-intnx-function-query/m-p/536413#M147412</guid>
      <dc:creator>scb</dc:creator>
      <dc:date>2019-02-18T09:33:49Z</dc:date>
    </item>
    <item>
      <title>Re: SAS intnx function query</title>
      <link>https://communities.sas.com/t5/SAS-Programming/SAS-intnx-function-query/m-p/536418#M147414</link>
      <description>&lt;P&gt;Yes, bur first off, please avoid shouting code at us, and finish macro variables with a dot, use the code window, and indentations!!&lt;/P&gt;
&lt;PRE&gt;data  _null_;
  a=put(intnx('year',today(),-1),year4.);
  b=put(intnx('year',today(),0),year4.);
  call symput("A",a);
  call symput("B",b);
  call symput("C",catx('/',a,b));
run;

%put A=&amp;amp;a.;
%put B=&amp;amp;b.;
%put C=&amp;amp;c.;&lt;/PRE&gt;
&lt;P&gt;The next question is, why put the today() result in a macro variable at all, or in fact the other two data items?&amp;nbsp; Each of these elements can simply be found by querying the today() function at the appropriate moment?&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;</description>
      <pubDate>Mon, 18 Feb 2019 09:40:43 GMT</pubDate>
      <guid>https://communities.sas.com/t5/SAS-Programming/SAS-intnx-function-query/m-p/536418#M147414</guid>
      <dc:creator>RW9</dc:creator>
      <dc:date>2019-02-18T09:40:43Z</dc:date>
    </item>
    <item>
      <title>Re: SAS intnx function query</title>
      <link>https://communities.sas.com/t5/SAS-Programming/SAS-intnx-function-query/m-p/536528#M147443</link>
      <description>&lt;P&gt;Once you have this much:&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;P&gt;%LET RUNDATE = TODAY();&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;P&gt;data&amp;nbsp; _null_;&lt;BR /&gt;call symput("A",put(intnx('YEAR',&amp;amp;RUNDATE,-1),YEAR4.));&lt;BR /&gt;run;&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;P&gt;That lets you continue with:&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;P&gt;%let B = %eval(&amp;amp;A + 1);&lt;/P&gt;
&lt;P&gt;%let C = &amp;amp;A/&amp;amp;B;&lt;/P&gt;</description>
      <pubDate>Mon, 18 Feb 2019 16:55:02 GMT</pubDate>
      <guid>https://communities.sas.com/t5/SAS-Programming/SAS-intnx-function-query/m-p/536528#M147443</guid>
      <dc:creator>Astounding</dc:creator>
      <dc:date>2019-02-18T16:55:02Z</dc:date>
    </item>
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