topic Hash Programming - Variable is not an Object in SAS Programming

Hash Programming - Variable is not an Object

theponcer — Mon, 24 Dec 2018 18:37:17 GMT

I am trying to do a hash merge. However, I keep getting an error that says "ERROR: DATA STEP Component Object failure. Aborted during the COMPILATION phase.
ERROR 557-185: Variable test is not an object."

data out_table;
set base_table;
if n=0 then set lookup_table;

if _n_ = 1 then do;
dcl hash test (dataset:'lookup_table');
	test.definekey('key');
	test.definedata('key','Var1');
	test.definedone();


rc_test=test.find();


run;

Anyone have any ideas what I am doing wrong? When I change the hash object to "test_t" it works.

Re: Hash Programming - Variable is not an Object

mkeintz — Mon, 24 Dec 2018 22:43:31 GMT

Do you have a variable named TEST in either base_table or lookup_table? If so then the SAS compiler already has a use for that name, and you can't also use the name test for another purpose.

True, when you use TEST as the name of a hash object, you could think of it as a "variable". But it's a variable whose value is a pointer to an object, which in turn contains all the data items and keys loaded into the hash object. That makes it a special kind of variable (i.e. not numeric or character). And unlike other variables created within a data step, it is automatically "retained" across observations. That's why you commonly see the INSTANTIATION of a hash object inside something like an "IF _N_ then do;" group of statements.

I'll let you look up the concept of hash object instantiation (as opposed to declaration), if needed.

Also, you appear to be missing an "END:" statement after the definedone method, prior to the find method.

Re: Hash Programming - Variable is not an Object

theponcer — Wed, 02 Jan 2019 17:29:20 GMT

Yup, that was the problem! I figured that was the issue, but couldn't figure out why SAS would be considering the hash table to be a variable name. Thanks for pointing me towards instantiation!