topic Re: how to assign values based on condition in SAS Programming

how to assign values based on condition

vraj1 — Sat, 06 Oct 2018 09:34:54 GMT

data t;
	set FDAT;
	period="A";
	if strip(EXT) = "pine" then 
		do;
			EXD = 5;
			output;
			EXD = 10;
			output;
			EXD = 15;
			output;
		end;
		
	if strip(EXT) = "Rdone" then 
		do;
			EXD = 2;
			output;
			EXD = 4;
			output;
			EXD = 6;
			output;
		end;

run;

if my variable EXT has pine in it then i want to assign new variable exd and randomly assign values 5,10,15 for all id's and the same with the next step as mentioned in the code.

Somehow it doesnt work and creates more records than existing dataset. I am not sure if the logic i am using is correct.

Any help?

Re: how to assign values based on condition

PeterClemmensen — Sat, 06 Oct 2018 10:59:14 GMT

2 things.

1) Since you use explicit output statements, you are not guaranteed to get the same number of rows in the two data sets. It will depend on the EXT variable.

2) Since you want to randomly assign values to the EXD variable if "EXT has pine in it", then your if statement is not sufficient.

There is not much to go on, but I think this is closer to what you want

data t;
	set FDAT;
	period="A";
   array valuespine [3] _temporary_ (5 10 15);
   array valuesRdone [3] _temporary_ (2 4 6);
	if findw(EXT,'pine', 'i')>0 then do;
         EXD=valuespine[rand("integer", 1, 3)];
	end;
	if findw(EXT,'Rdone', 'i')>0 then do;
         EXD=valuesRdone[rand("integer", 1, 3)];
	end;
run;

Re: how to assign values based on condition

VDD — Sat, 06 Oct 2018 14:22:51 GMT

data t;
	set FDAT;
	period="A";
	if strip(EXT) = "pine" then 
		do I = 5 to 15 by 5;
			EXD = i;
			output;
		end;
		
	if strip(EXT) = "Rdone" then 
		do I = 2 to 6 by 2;
			EXD = i;
			output;
		end;
run;

Re: how to assign values based on condition

vraj1 — Sun, 07 Oct 2018 05:37:09 GMT

somehow it does not resolve if i use condition if period="A" then do;

i get empty values.

attached test data.