topic Re: Replacing missing IDs with the previous ones based on Date condition. in SAS Programming

Replacing missing IDs with the previous ones based on Date condition.

Saba1 — Fri, 28 Sep 2018 06:43:06 GMT

I have the following dataset:

Data have;
input ID_W Date_F: mmddyy10. ID_Fund;
datalines;
105246 06/30/2016 10
105246 09/30/2016 10
105246 12/31/2016 10
. 03/31/2017 10
. 06/30/2017 10
. 09/30/2017 10
. 12/31/2017 10
105250 12/31/2012 12
. 06/30/2017 12
. 09/30/2017 12
. 12/31/2017 12
105256 03/31/2016 25
105256 09/30/2016 25
. 06/30/2017 25
. 09/30/2017 25
run;

I want the below:

Data want;
input ID_W Date_F: mmddyy10. ID_Fund;
datalines;
105246 06/30/2016 10
105246 09/30/2016 10
105246 12/31/2016 10
105246 03/31/2017 10
105246 06/30/2017 10
105246 09/30/2017 10
105246 12/31/2017 10
105250 12/31/2012 12
. 06/30/2015 12
. 09/30/2017 12
. 12/31/2017 12
105256 03/31/2016 25
105256 09/30/2016 25
105256 06/30/2017 25
105256 09/30/2017 25
run;

This means for each ID_Fund, if ID_W exists for the dates of the year 2016, then it should replace the missing ID_Ws for all the dates of the year 2017. However, if ID_W exists for any year before 2016, then it should not replace the missing values.

Thanks.

Replacing missing IDs with the previous ones based on Date condition

Saba1 — Fri, 28 Sep 2018 07:00:23 GMT

I have the following dataset:

Data have;
input ID_W Date_F: mmddyy10. ID_Fund;
datalines;
105246 06/30/2016 10
105246 09/30/2016 10
105246 12/31/2016 10
. 03/31/2017 10
. 06/30/2017 10
. 09/30/2017 10
. 12/31/2017 10
105250 12/31/2012 12
. 06/30/2017 12
. 09/30/2017 12
. 12/31/2017 12
105256 03/31/2016 25
105256 09/30/2016 25
. 06/30/2017 25
. 09/30/2017 25
run;

I want the below:

Data want;
input ID_W Date_F: mmddyy10. ID_Fund;
datalines;
105246 06/30/2016 10
105246 09/30/2016 10
105246 12/31/2016 10
105246 03/31/2017 10
105246 06/30/2017 10
105246 09/30/2017 10
105246 12/31/2017 10
105250 12/31/2012 12
. 06/30/2015 12
. 09/30/2017 12
. 12/31/2017 12
105256 03/31/2016 25
105256 09/30/2016 25
105256 06/30/2017 25
105256 09/30/2017 25
run;

Thanks.

Re: Replacing missing IDs with the previous ones based on Date condition.

Kurt_Bremser — Fri, 28 Sep 2018 07:20:12 GMT

Use a retained variable to keep values across observations:

Data have;
input ID_W Date_F: mmddyy10. ID_Fund;
format Date_F yymmddd10.;
datalines;
105246 06/30/2016 10
105246 09/30/2016 10
105246 12/31/2016 10
. 03/31/2017 10
. 06/30/2017 10
. 09/30/2017 10
. 12/31/2017 10
105250 12/31/2012 12
. 06/30/2017 12
. 09/30/2017 12
. 12/31/2017 12
105256 03/31/2016 25
105256 09/30/2016 25
. 06/30/2017 25
. 09/30/2017 25
;
run;

data want;
set have;
by id_fund;
retain _w;
if first.id_fund then _w = .;
if year(date_f) = 2016 and id_w ne . then _w = id_w;
if year(date_f) = 2017 and id_w = . and _w ne . then id_w = _w;
drop _w;
run;

proc print data=want noobs;
run;

Result:

 ID_W         Date_F    ID_Fund

105246    2016-06-30       10  
105246    2016-09-30       10  
105246    2016-12-31       10  
105246    2017-03-31       10  
105246    2017-06-30       10  
105246    2017-09-30       10  
105246    2017-12-31       10  
105250    2012-12-31       12  
     .    2017-06-30       12  
     .    2017-09-30       12  
     .    2017-12-31       12  
105256    2016-03-31       25  
105256    2016-09-30       25  
105256    2017-06-30       25  
105256    2017-09-30       25

Re: Replacing missing IDs with the previous ones based on Date condition.

RW9 — Fri, 28 Sep 2018 07:24:42 GMT

Something like:

data have;
  input id_w date_f: mmddyy10. id_fund;
  format date_f date9.;
datalines;
105246 06/30/2016 10
105246 09/30/2016 10
105246 12/31/2016 10
. 03/31/2017 10
. 06/30/2017 10
. 09/30/2017 10
. 12/31/2017 10
105250 12/31/2012 12
. 06/30/2017 12
. 09/30/2017 12
. 12/31/2017 12
105256 03/31/2016 25
105256 09/30/2016 25
. 06/30/2017 25
. 09/30/2017 25
;
run;

data want;
  set have;
  retain lstid;
  if id_w ne . and year(date_f)=2016 then lstid=id_w;
  if id_w ne . and id_w ne lstid then lstid=.;
  if id_w=. and year(date_f) ge 2016 then id_w=lstid;
run;

Re: Replacing missing IDs with the previous ones based on Date condition.

mkeintz — Fri, 28 Sep 2018 11:55:33 GMT

Here is a solution that use the SET ... POINT= instead of retained variables.

Data have;
input ID_W Date_F: mmddyy10. ID_Fund;
format Date_F yymmddd10.;
datalines;
105246 06/30/2016 10
105246 09/30/2016 10
105246 12/31/2016 10
. 03/31/2017 10
. 06/30/2017 10
. 09/30/2017 10
. 12/31/2017 10
105250 12/31/2012 12
. 06/30/2017 12
. 09/30/2017 12
. 12/31/2017 12
105256 03/31/2016 25
105256 09/30/2016 25
. 06/30/2017 25
. 09/30/2017 25
run;

data want;
  set have ;
  by id_fund;;
  if first.id_fund then ptr=.;
  if year(date_f)=2016 then ptr=_n_;
  if id_w=. and ptr^=. then set have (keep=id_w) point=ptr;
run;

The ptr variable keeps track of the position of most recent 2016 record within a BY ID_FUND group. When you are concerned with updating only the ID_W variable, it has no particular advantage over the retain approach. But if you wanted to recall (say) 20 variables from the 2016 record when ID_W is missing, then all you would need to do is list those 20 variables in the "keep=" parameter in the SET .... POINT= statement.

Re: Replacing missing IDs with the previous ones based on Date condition.

Saba1 — Sat, 29 Sep 2018 12:38:50 GMT

thanks a lot. it works really well.

Re: Replacing missing IDs with the previous ones based on Date condition.

Saba1 — Sat, 29 Sep 2018 12:39:14 GMT

thank you for the guidance.

Re: Replacing missing IDs with the previous ones based on Date condition.

Saba1 — Sat, 29 Sep 2018 12:39:32 GMT

thanks a lot.