topic Re: Count Consecutive Days over 90 degrees each period of Jan - Aug 1999 - 2018 in SAS Programming

Count Consecutive Days over 90 degrees each Month

KALLEN — Tue, 18 Sep 2018 14:43:45 GMT

How do I count how many consecutive days are 90 degrees or over each August (i.e. 19 consecutive days over 90 in August 1999)?

i.e. "What is longest sequence of consecutive days with temperature greater than 90?"

My code:

data demo5.aug_weather_consec;
    set demo5.aug_weather1;   
	if Max_Temp >= 90 then consec+1;
	else if Max_Temp < 90 then consec=0;
run;

proc means data=demo5.aug_weather_consec max;
	var consec; 
	by date;
run;

Desired result:

August Consecutive Days at/or Above 90
August, Year	August Consecutive Days at/or Above 90
1999	18
2000	16
2001	9
2002	27
2003	15
2004	13
2005	6
2006	7
2007	26
2008	6
2009	23
2010	23
2011	16
2012	16
2013	13
2014	7
2015	30
2016	12
2017	17
2018	19

I have attached my dataset.

Re: Count Consecutive Days over 90 degrees each Month

PaigeMiller — Mon, 17 Sep 2018 22:17:00 GMT

You haven't actually asked a question.

Also, your title says you want consecutive days, but your first sentence doesn't say consecutive. So which is it?

Re: Count Consecutive Days over 90 degrees each Month

data_null__ — Mon, 17 Sep 2018 22:35:15 GMT

I haven't answered the question you did not ask but is something I want to show you.

This outputs all 90+ days with start and end dates for consecutive runs. _FREQ_ is the day length of the run.

filename aug clipbrd;
data aug;
   infile aug;
   input date :date. degrees;
   gt90 = degrees ge 90;
   format date date11.;
   run;
proc summary nway;
   by gt90 notsorted;
   class date;
   format date monyy.;
   output out=runs(drop=_type_ where=(gt90 eq 1)) idgroup(out(date)=start) idgroup(last out(date)=end);
   format start: end: date11.;
   run;
proc print;
   run;

Re: Count Consecutive Days over 90 degrees each Month

ballardw — Mon, 17 Sep 2018 23:29:48 GMT

From your example data and what I think is your expected result the question you are asking is "what is longest sequence of consecutive days with temperature greater than 90". Is that a correct interpretation?

Re: Count Consecutive Days over 90 degrees each Month

KALLEN — Tue, 18 Sep 2018 14:00:07 GMT

I have revised the question.

Re: Count Consecutive Days over 90 degrees each Month

KALLEN — Tue, 18 Sep 2018 14:20:01 GMT

Yes, thank you.

Re: Count Consecutive Days over 90 degrees each Month

data_null__ — Tue, 18 Sep 2018 15:02:41 GMT

data aug;
   infile aug;
   input date :date. degrees;
   year = year(date);
   gt90 = degrees ge 90;
   format date date11.;
   run;
proc summary nway data=aug;
   by gt90 notsorted;
   class date;
   format date monyy7.;
   output out=runs(drop=_type_ rename=(_freq_=runlength) where=(gt90 eq 1)) idgroup(out(date)=start) idgroup(last out(date)=end);
   format start: end: date11.;
   run;
proc summary data=runs nway;
   class date;
   output out=maxrun(drop=_:) max(runlength)=;
   run;

Re: Count Consecutive Days over 90 degrees each Month

KALLEN — Tue, 18 Sep 2018 16:31:44 GMT

This code and output look great. However, I am having trouble importing the data aug. When I run the first block of code, I get the error message below.

data aug;
   infile aug;
   input date :date. degrees;
   year = year(date);
   gt90 = degrees ge 90;
   format date date11.;
   run;

ERROR: I/O failure.
NOTE: The SAS System stopped processing this step because of errors.
WARNING: The data set WORK.AUG may be incomplete. When this step was stopped there were 0 observations and 4 variables.
WARNING: Data set WORK.AUG was not replaced because this step was stopped.

What could I be doing wrong when importing the data or refer to the dataset in the data step?

Re: Count Consecutive Days over 90 degrees each Month

data_null__ — Tue, 18 Sep 2018 16:45:02 GMT

@KALLEN wrote:

This code and output look great. However, I am having trouble importing the data aug. When I run the first block of code, I get the error message below.
data aug;
   infile aug;
   input date :date. degrees;
   year = year(date);
   gt90 = degrees ge 90;
   format date date11.;
   run;
ERROR: I/O failure.
NOTE: The SAS System stopped processing this step because of errors.
WARNING: The data set WORK.AUG may be incomplete. When this step was stopped there were 0 observations and 4 variables.
WARNING: Data set WORK.AUG was not replaced because this step was stopped.

What could I be doing wrong when importing the data or refer to the dataset in the data step?

You still IMPORT your data the same way as you have done. You just need to create the indicator and then run the PROC SUMMARY steps.

Re: Count Consecutive Days over 90 degrees each Month

KALLEN — Tue, 18 Sep 2018 17:13:38 GMT

Great, this worked for me - just had to alter the name of the dataset.

Thanks again.

Re: Count Consecutive Days over 90 degrees each period of Jan - Aug 1999 - 2018

KALLEN — Thu, 20 Sep 2018 17:19:30 GMT

I have a similar problem, but now I need to view the longest sequence of consecutive days with temperature greater than 90° for each period Jan-Aug 1999 - 2018 (YTD).

Below is similar code I used from the last post, but now I need to change proc summary such that the data from Jan - Aug for runlength are added together for each year:

/* create indicator variable for Max Temp >= 90 (gt90)  */
data ytd_weather1;
   set demo5.ytd_weather;
   gt90 = Max_Temp ge 90;
   format date date11.;
   run;

  /* create start and end dates for the beginning and end of each month */
proc summary nway data=ytd_weather1;
   by gt90 notsorted;
   class date;
   format date monyy7.;
   output out=runs(drop=_type_ rename=(_freq_=runlength) where=(gt90 eq 1)) idgroup(out(date)=start) idgroup(last out(date)=end);
   format start: end: date11.;
   run;

/* run the proc summary to view the longest sequence of consecutive days with temperature greater than 90 for each YTD AUG 1999 - 2018 */ 
proc summary data=runs nway;
   class date;
   output out=maxrun(drop=_:) max(runlength)=;
   run;

current output:

Date	runlength
Apr1999	2
May1999	5
Jun1999	10
Jul1999	9
Aug1999	18
Apr2000	5
May2000	9
Jun2000	8
Jul2000	31
Aug2000	16
Apr2001	1
May2001	9
Jun2001	13
Jul2001	31
Aug2001	9
Apr2002	2
May2002	4
Jun2002	24
Jul2002	10
Aug2002	28
May2003	8
Jun2003	24
Jul2003	28
Aug2003	15
May2004	11
Jun2004	21
Jul2004	23
Aug2004	13
May2005	7
Jun2005	26
Jul2005	26
Aug2005	6
Apr2006	2
May2006	14
Jun2006	25
Jul2006	19
Aug2006	7
May2007	5
Jun2007	18
Jul2007	7
Aug2007	27
Apr2008	1
May2008	7
Jun2008	23
Jul2008	7
Aug2008	6
May2009	12
Jun2009	8
Jul2009	31
Aug2009	23
May2010	6
Jun2010	28
Jul2010	13
Aug2010	23
Apr2011	1
May2011	7
Jun2011	30
Jul2011	28
Aug2011	17
Mar2012	1
Apr2012	6
May2012	15
Jun2012	30
Jul2012	15
Aug2012	16
Apr2013	2
May2013	7
Jun2013	30
Jul2013	12
Aug2013	13
May2014	6
Jun2014	30
Jul2014	15
Aug2014	7
May2015	3
Jun2015	30
Jul2015	31
Aug2015	31
May2016	6
Jun2016	25
Jul2016	30
Aug2016	12
Mar2017	1
Apr2017	2
May2017	4
Jun2017	28
Jul2017	15
Aug2017	17
Apr2018	2
May2018	14
Jun2018	15
Jul2018	21
Aug2018	19

desired output:

Date	runlength
1999	44
2000	69
2001	63
2002	68
2003	75
2004	68
2005	65

etc to 2018

Thanks.

Re: Count Consecutive Days over 90 degrees each period of Jan - Aug 1999 - 2018

KALLEN — Thu, 20 Sep 2018 18:10:13 GMT

I had to delete obs where runlength=1 and then add the proc timeseries step to convert monthly to annual data:

/* drop any obs where runlength=1 because that is not a consecutive day >=90 */
data maxrun;
 set maxrun;
 if runlength=1 then delete;
run;

/*convert monthly data to yearly data by adding sum of runlength */
proc timeseries data=maxrun out=runs_ytd;
 id date interval=year accumulate=total;
 var runlength;
run;

This gave me the expected output.