<?xml version="1.0" encoding="UTF-8"?>
<rss xmlns:content="http://purl.org/rss/1.0/modules/content/" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#" xmlns:taxo="http://purl.org/rss/1.0/modules/taxonomy/" version="2.0">
  <channel>
    <title>topic Re: How to count consecutive days? in New SAS User</title>
    <link>https://communities.sas.com/t5/New-SAS-User/How-to-count-consecutive-days/m-p/538945#M7005</link>
    <description>&lt;PRE&gt;&lt;CODE class=" language-sas"&gt;data test1;
    set test;
    by id;
    prev_date=lag(servicedate);
    if not first.id and intck('month',prev_date,servicedate,'c')&amp;gt;=6
        then newdate=date;
    format newdate mmddyy10.;
run;&lt;/CODE&gt;&lt;/PRE&gt;
&lt;P&gt;Use the INTCK function to determine how many months have elapsed between the two dates.&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;P&gt;I note, as did&amp;nbsp;&lt;a href="https://communities.sas.com/t5/user/viewprofilepage/user-id/15475"&gt;@andreas_lds&lt;/a&gt;&amp;nbsp;that your word description does not match the output you say you want.&lt;/P&gt;</description>
    <pubDate>Wed, 27 Feb 2019 12:48:07 GMT</pubDate>
    <dc:creator>PaigeMiller</dc:creator>
    <dc:date>2019-02-27T12:48:07Z</dc:date>
    <item>
      <title>How to count consecutive days?</title>
      <link>https://communities.sas.com/t5/New-SAS-User/How-to-count-consecutive-days/m-p/538765#M6987</link>
      <description>&lt;P&gt;Hello,&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;P&gt;i have a data set with id and service date and i want to know if each service date are 6 month apart or not. i use the lag function but it give me a weird result. Please help me figure out how this works. thank you so much.&lt;/P&gt;
&lt;P&gt;&lt;BR /&gt;data test1;&lt;BR /&gt;set test;&lt;BR /&gt;by id;&lt;BR /&gt;if first.id then date=.;&lt;BR /&gt;else date = lag(servicedate);&lt;BR /&gt;format date mmddyy10.;&lt;BR /&gt;run;&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;TABLE width="322"&gt;
&lt;TBODY&gt;
&lt;TR&gt;
&lt;TD width="69"&gt;id&lt;/TD&gt;
&lt;TD width="69"&gt;Count&lt;/TD&gt;
&lt;TD width="89"&gt;servicedate&lt;/TD&gt;
&lt;TD width="95"&gt;year&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;1&lt;/TD&gt;
&lt;TD&gt;0&lt;/TD&gt;
&lt;TD&gt;11/8/2013&lt;/TD&gt;
&lt;TD&gt;2013&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;1&lt;/TD&gt;
&lt;TD&gt;20&lt;/TD&gt;
&lt;TD&gt;11/7/2014&lt;/TD&gt;
&lt;TD&gt;2014&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;1&lt;/TD&gt;
&lt;TD&gt;20&lt;/TD&gt;
&lt;TD&gt;2/2/2015&lt;/TD&gt;
&lt;TD&gt;2015&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;1&lt;/TD&gt;
&lt;TD&gt;20&lt;/TD&gt;
&lt;TD&gt;4/23/2015&lt;/TD&gt;
&lt;TD&gt;2015&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;1&lt;/TD&gt;
&lt;TD&gt;0&lt;/TD&gt;
&lt;TD&gt;10/8/2015&lt;/TD&gt;
&lt;TD&gt;2015&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;1&lt;/TD&gt;
&lt;TD&gt;0&lt;/TD&gt;
&lt;TD&gt;1/5/2016&lt;/TD&gt;
&lt;TD&gt;2016&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;1&lt;/TD&gt;
&lt;TD&gt;20&lt;/TD&gt;
&lt;TD&gt;4/6/2016&lt;/TD&gt;
&lt;TD&gt;2016&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;1&lt;/TD&gt;
&lt;TD&gt;40&lt;/TD&gt;
&lt;TD&gt;6/30/2016&lt;/TD&gt;
&lt;TD&gt;2016&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;2&lt;/TD&gt;
&lt;TD&gt;20&lt;/TD&gt;
&lt;TD&gt;8/21/2015&lt;/TD&gt;
&lt;TD&gt;2015&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;2&lt;/TD&gt;
&lt;TD&gt;20&lt;/TD&gt;
&lt;TD&gt;8/21/2015&lt;/TD&gt;
&lt;TD&gt;2015&lt;/TD&gt;
&lt;/TR&gt;
&lt;/TBODY&gt;
&lt;/TABLE&gt;</description>
      <pubDate>Tue, 26 Feb 2019 19:16:01 GMT</pubDate>
      <guid>https://communities.sas.com/t5/New-SAS-User/How-to-count-consecutive-days/m-p/538765#M6987</guid>
      <dc:creator>juliajulia</dc:creator>
      <dc:date>2019-02-26T19:16:01Z</dc:date>
    </item>
    <item>
      <title>Re: How to count consecutive days?</title>
      <link>https://communities.sas.com/t5/New-SAS-User/How-to-count-consecutive-days/m-p/538767#M6988</link>
      <description>&lt;PRE&gt;&lt;CODE class=" language-sas"&gt;data test1;
set test;
by id;
prev_date=lag(servicedate);
if first.id then date=.;
else date = prev_date;
format date mmddyy10.;
run;&lt;/CODE&gt;&lt;/PRE&gt;</description>
      <pubDate>Tue, 26 Feb 2019 19:18:23 GMT</pubDate>
      <guid>https://communities.sas.com/t5/New-SAS-User/How-to-count-consecutive-days/m-p/538767#M6988</guid>
      <dc:creator>PaigeMiller</dc:creator>
      <dc:date>2019-02-26T19:18:23Z</dc:date>
    </item>
    <item>
      <title>Re: How to count consecutive days?</title>
      <link>https://communities.sas.com/t5/New-SAS-User/How-to-count-consecutive-days/m-p/538820#M6989</link>
      <description>&lt;P&gt;Thanks.&lt;/P&gt;
&lt;P&gt;i found my question is more complicated than i thought. i actually need to find those dates that has 6 month or greater interval with any of the previous date value. for example,&amp;nbsp; the value of the newDate variable only keep those dates that have 6 month or greater than any of the previous dates in the servicedate.&amp;nbsp; How to create the newDate variable? please help.&lt;/P&gt;
&lt;TABLE width="239"&gt;
&lt;TBODY&gt;
&lt;TR&gt;
&lt;TD width="69"&gt;ID&lt;/TD&gt;
&lt;TD width="83"&gt;servicedate&lt;/TD&gt;
&lt;TD width="87"&gt;NewDate&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;1&lt;/TD&gt;
&lt;TD&gt;11/8/2013&lt;/TD&gt;
&lt;TD&gt;11/8/2013&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;1&lt;/TD&gt;
&lt;TD&gt;12/7/2013&lt;/TD&gt;
&lt;TD&gt;&amp;nbsp;&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;1&lt;/TD&gt;
&lt;TD&gt;2/2/2014&lt;/TD&gt;
&lt;TD&gt;2/2/2014&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;1&lt;/TD&gt;
&lt;TD&gt;4/23/2014&lt;/TD&gt;
&lt;TD&gt;&amp;nbsp;&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;1&lt;/TD&gt;
&lt;TD&gt;9/8/2014&lt;/TD&gt;
&lt;TD&gt;9/8/2014&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;1&lt;/TD&gt;
&lt;TD&gt;12/5/2014&lt;/TD&gt;
&lt;TD&gt;&amp;nbsp;&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;1&lt;/TD&gt;
&lt;TD&gt;4/6/2015&lt;/TD&gt;
&lt;TD&gt;4/6/2015&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;2&lt;/TD&gt;
&lt;TD&gt;3/17/2016&lt;/TD&gt;
&lt;TD&gt;3/17/2016&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;2&lt;/TD&gt;
&lt;TD&gt;4/17/2016&lt;/TD&gt;
&lt;TD&gt;&amp;nbsp;&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;2&lt;/TD&gt;
&lt;TD&gt;9/18/2016&lt;/TD&gt;
&lt;TD&gt;9/18/2016&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;2&lt;/TD&gt;
&lt;TD&gt;12/5/2016&lt;/TD&gt;
&lt;TD&gt;&amp;nbsp;&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;2&lt;/TD&gt;
&lt;TD&gt;12/9/2016&lt;/TD&gt;
&lt;TD&gt;&amp;nbsp;&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;2&lt;/TD&gt;
&lt;TD&gt;4/9/2016&lt;/TD&gt;
&lt;TD&gt;4/9/2016&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;2&lt;/TD&gt;
&lt;TD&gt;11/21/2016&lt;/TD&gt;
&lt;TD&gt;11/21/2016&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;2&lt;/TD&gt;
&lt;TD&gt;11/21/2016&lt;/TD&gt;
&lt;TD&gt;&amp;nbsp;&lt;/TD&gt;
&lt;/TR&gt;
&lt;/TBODY&gt;
&lt;/TABLE&gt;</description>
      <pubDate>Tue, 26 Feb 2019 21:30:22 GMT</pubDate>
      <guid>https://communities.sas.com/t5/New-SAS-User/How-to-count-consecutive-days/m-p/538820#M6989</guid>
      <dc:creator>juliajulia</dc:creator>
      <dc:date>2019-02-26T21:30:22Z</dc:date>
    </item>
    <item>
      <title>Re: How to count consecutive days?</title>
      <link>https://communities.sas.com/t5/New-SAS-User/How-to-count-consecutive-days/m-p/538934#M7004</link>
      <description>&lt;P&gt;Sorry, but i can't understand the logic you have described. Why is "4/23/2014" not in the NewDate variable? There are observations with id=1 having a difference of more than six months-&lt;/P&gt;
&lt;BLOCKQUOTE&gt;&lt;HR /&gt;&lt;a href="https://communities.sas.com/t5/user/viewprofilepage/user-id/16488"&gt;@juliajulia&lt;/a&gt;&amp;nbsp;wrote:&lt;BR /&gt;
&lt;P&gt;Thanks.&lt;/P&gt;
&lt;P&gt;i found my question is more complicated than i thought. i actually need to find those dates that has 6 month or greater interval with any of the previous date value. for example,&amp;nbsp; the value of the newDate variable only keep those dates that have 6 month or greater than any of the previous dates in the servicedate.&amp;nbsp; How to create the newDate variable? please help.&lt;/P&gt;
&lt;TABLE width="239"&gt;
&lt;TBODY&gt;
&lt;TR&gt;
&lt;TD width="69"&gt;ID&lt;/TD&gt;
&lt;TD width="83"&gt;servicedate&lt;/TD&gt;
&lt;TD width="87"&gt;NewDate&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;1&lt;/TD&gt;
&lt;TD&gt;11/8/2013&lt;/TD&gt;
&lt;TD&gt;11/8/2013&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;1&lt;/TD&gt;
&lt;TD&gt;12/7/2013&lt;/TD&gt;
&lt;TD&gt;&amp;nbsp;&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;1&lt;/TD&gt;
&lt;TD&gt;2/2/2014&lt;/TD&gt;
&lt;TD&gt;2/2/2014&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;1&lt;/TD&gt;
&lt;TD&gt;4/23/2014&lt;/TD&gt;
&lt;TD&gt;&amp;nbsp;&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;1&lt;/TD&gt;
&lt;TD&gt;9/8/2014&lt;/TD&gt;
&lt;TD&gt;9/8/2014&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;1&lt;/TD&gt;
&lt;TD&gt;12/5/2014&lt;/TD&gt;
&lt;TD&gt;&amp;nbsp;&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;1&lt;/TD&gt;
&lt;TD&gt;4/6/2015&lt;/TD&gt;
&lt;TD&gt;4/6/2015&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;2&lt;/TD&gt;
&lt;TD&gt;3/17/2016&lt;/TD&gt;
&lt;TD&gt;3/17/2016&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;2&lt;/TD&gt;
&lt;TD&gt;4/17/2016&lt;/TD&gt;
&lt;TD&gt;&amp;nbsp;&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;2&lt;/TD&gt;
&lt;TD&gt;9/18/2016&lt;/TD&gt;
&lt;TD&gt;9/18/2016&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;2&lt;/TD&gt;
&lt;TD&gt;12/5/2016&lt;/TD&gt;
&lt;TD&gt;&amp;nbsp;&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;2&lt;/TD&gt;
&lt;TD&gt;12/9/2016&lt;/TD&gt;
&lt;TD&gt;&amp;nbsp;&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;2&lt;/TD&gt;
&lt;TD&gt;4/9/2016&lt;/TD&gt;
&lt;TD&gt;4/9/2016&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;2&lt;/TD&gt;
&lt;TD&gt;11/21/2016&lt;/TD&gt;
&lt;TD&gt;11/21/2016&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;2&lt;/TD&gt;
&lt;TD&gt;11/21/2016&lt;/TD&gt;
&lt;TD&gt;&amp;nbsp;&lt;/TD&gt;
&lt;/TR&gt;
&lt;/TBODY&gt;
&lt;/TABLE&gt;
&lt;HR /&gt;&lt;/BLOCKQUOTE&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;</description>
      <pubDate>Wed, 27 Feb 2019 12:17:18 GMT</pubDate>
      <guid>https://communities.sas.com/t5/New-SAS-User/How-to-count-consecutive-days/m-p/538934#M7004</guid>
      <dc:creator>andreas_lds</dc:creator>
      <dc:date>2019-02-27T12:17:18Z</dc:date>
    </item>
    <item>
      <title>Re: How to count consecutive days?</title>
      <link>https://communities.sas.com/t5/New-SAS-User/How-to-count-consecutive-days/m-p/538945#M7005</link>
      <description>&lt;PRE&gt;&lt;CODE class=" language-sas"&gt;data test1;
    set test;
    by id;
    prev_date=lag(servicedate);
    if not first.id and intck('month',prev_date,servicedate,'c')&amp;gt;=6
        then newdate=date;
    format newdate mmddyy10.;
run;&lt;/CODE&gt;&lt;/PRE&gt;
&lt;P&gt;Use the INTCK function to determine how many months have elapsed between the two dates.&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;P&gt;I note, as did&amp;nbsp;&lt;a href="https://communities.sas.com/t5/user/viewprofilepage/user-id/15475"&gt;@andreas_lds&lt;/a&gt;&amp;nbsp;that your word description does not match the output you say you want.&lt;/P&gt;</description>
      <pubDate>Wed, 27 Feb 2019 12:48:07 GMT</pubDate>
      <guid>https://communities.sas.com/t5/New-SAS-User/How-to-count-consecutive-days/m-p/538945#M7005</guid>
      <dc:creator>PaigeMiller</dc:creator>
      <dc:date>2019-02-27T12:48:07Z</dc:date>
    </item>
  </channel>
</rss>

