topic Re: find() in New SAS User

find()

nirupama1 — Sat, 01 Dec 2018 15:44:23 GMT

data _null_;
xyz='She sells seashells? Yes, she does.';
startposexp=1-23;
whereisShe_ineg22=find(xyz,'She','i',startposexp);
put whereisShe_ineg22=;
run;

I should receive output whereisShe_ineg22=1 instead I am getting whereisShe_ineg22=14.
why?Let me know.

Thanks,

Nirupama

Re: find()

Astounding — Sat, 01 Dec 2018 15:53:46 GMT

You should be using a value of 1 for STARTPOSEXP. You are actually using a value of -22 (after performing math for 1 minus 23). So the software computes the starting position by moving backwards from the right-hand side of the string. Details are in the documentation for FIND.

Re: find()

ballardw — Mon, 03 Dec 2018 22:33:53 GMT

She sells seashells? Yes, she does.
                     ^
                     Position 22
             ^
             Postion 14

So you started searching backwards ad the Y.