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<rss xmlns:content="http://purl.org/rss/1.0/modules/content/" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#" xmlns:taxo="http://purl.org/rss/1.0/modules/taxonomy/" version="2.0">
  <channel>
    <title>topic deleting observations conditioned by previous observations in New SAS User</title>
    <link>https://communities.sas.com/t5/New-SAS-User/deleting-observations-conditioned-by-previous-observations/m-p/672495#M23432</link>
    <description>&lt;P&gt;Hi&lt;/P&gt;&lt;P&gt;I need help removing observations depending on previous observations.&lt;/P&gt;&lt;P&gt;I have&lt;/P&gt;&lt;P&gt;ID&amp;nbsp;&amp;nbsp; HA&lt;/P&gt;&lt;P&gt;1&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 1&lt;/P&gt;&lt;P&gt;1&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;3&lt;/P&gt;&lt;P&gt;2&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 3&lt;/P&gt;&lt;P&gt;2&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 3&lt;/P&gt;&lt;P&gt;2&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 3&lt;/P&gt;&lt;P&gt;3&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 2&lt;/P&gt;&lt;P&gt;3&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 3&lt;/P&gt;&lt;P&gt;3&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 3&lt;/P&gt;&lt;P&gt;4&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;1&lt;/P&gt;&lt;P&gt;4&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;2&lt;/P&gt;&lt;P&gt;4&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;3&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;I want&lt;/P&gt;&lt;P&gt;ID&amp;nbsp;&amp;nbsp; HA&lt;/P&gt;&lt;P&gt;1&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 1&lt;/P&gt;&lt;P&gt;2&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 3&lt;/P&gt;&lt;P&gt;2&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 3&lt;/P&gt;&lt;P&gt;2&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 3&lt;/P&gt;&lt;P&gt;3&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 2&lt;/P&gt;&lt;P&gt;4&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;1&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;For each ID I want to keep the observation where HA=1 or HA=2. If one ID has both HA=1 and HA=2, I only want to keep the one where HA=1. If an ID has neither HA=1 nor 2 (ie. only HA=3), then I want to keep all the observations with HA=3.&lt;/P&gt;&lt;P&gt;Any suggestions?&lt;/P&gt;</description>
    <pubDate>Mon, 27 Jul 2020 11:38:11 GMT</pubDate>
    <dc:creator>RTN</dc:creator>
    <dc:date>2020-07-27T11:38:11Z</dc:date>
    <item>
      <title>deleting observations conditioned by previous observations</title>
      <link>https://communities.sas.com/t5/New-SAS-User/deleting-observations-conditioned-by-previous-observations/m-p/672495#M23432</link>
      <description>&lt;P&gt;Hi&lt;/P&gt;&lt;P&gt;I need help removing observations depending on previous observations.&lt;/P&gt;&lt;P&gt;I have&lt;/P&gt;&lt;P&gt;ID&amp;nbsp;&amp;nbsp; HA&lt;/P&gt;&lt;P&gt;1&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 1&lt;/P&gt;&lt;P&gt;1&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;3&lt;/P&gt;&lt;P&gt;2&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 3&lt;/P&gt;&lt;P&gt;2&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 3&lt;/P&gt;&lt;P&gt;2&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 3&lt;/P&gt;&lt;P&gt;3&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 2&lt;/P&gt;&lt;P&gt;3&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 3&lt;/P&gt;&lt;P&gt;3&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 3&lt;/P&gt;&lt;P&gt;4&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;1&lt;/P&gt;&lt;P&gt;4&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;2&lt;/P&gt;&lt;P&gt;4&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;3&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;I want&lt;/P&gt;&lt;P&gt;ID&amp;nbsp;&amp;nbsp; HA&lt;/P&gt;&lt;P&gt;1&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 1&lt;/P&gt;&lt;P&gt;2&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 3&lt;/P&gt;&lt;P&gt;2&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 3&lt;/P&gt;&lt;P&gt;2&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 3&lt;/P&gt;&lt;P&gt;3&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 2&lt;/P&gt;&lt;P&gt;4&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;1&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;For each ID I want to keep the observation where HA=1 or HA=2. If one ID has both HA=1 and HA=2, I only want to keep the one where HA=1. If an ID has neither HA=1 nor 2 (ie. only HA=3), then I want to keep all the observations with HA=3.&lt;/P&gt;&lt;P&gt;Any suggestions?&lt;/P&gt;</description>
      <pubDate>Mon, 27 Jul 2020 11:38:11 GMT</pubDate>
      <guid>https://communities.sas.com/t5/New-SAS-User/deleting-observations-conditioned-by-previous-observations/m-p/672495#M23432</guid>
      <dc:creator>RTN</dc:creator>
      <dc:date>2020-07-27T11:38:11Z</dc:date>
    </item>
    <item>
      <title>Re: deleting observations conditioned by previous observations</title>
      <link>https://communities.sas.com/t5/New-SAS-User/deleting-observations-conditioned-by-previous-observations/m-p/672498#M23433</link>
      <description>&lt;BLOCKQUOTE&gt;&lt;HR /&gt;&lt;a href="https://communities.sas.com/t5/user/viewprofilepage/user-id/299137"&gt;@RTN&lt;/a&gt;&amp;nbsp;wrote:&lt;BR /&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;P&gt;For each ID I want to keep the observation where HA=1 or HA=2. If one ID has both HA=1 and HA=2, I only want to keep the one where HA=1. If an ID has neither HA=1 nor 2 (ie. only HA=3), then I want to keep all the observations with HA=3.&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;HR /&gt;&lt;/BLOCKQUOTE&gt;
&lt;P&gt;What about the third case, where one ID has either HA=1 or HA=2, but not both?&lt;/P&gt;</description>
      <pubDate>Mon, 27 Jul 2020 11:59:40 GMT</pubDate>
      <guid>https://communities.sas.com/t5/New-SAS-User/deleting-observations-conditioned-by-previous-observations/m-p/672498#M23433</guid>
      <dc:creator>PaigeMiller</dc:creator>
      <dc:date>2020-07-27T11:59:40Z</dc:date>
    </item>
    <item>
      <title>Re: deleting observations conditioned by previous observations</title>
      <link>https://communities.sas.com/t5/New-SAS-User/deleting-observations-conditioned-by-previous-observations/m-p/672501#M23434</link>
      <description>When one ID has neither HA=1 nor HA=2, then I want to keep all observations.</description>
      <pubDate>Mon, 27 Jul 2020 12:06:17 GMT</pubDate>
      <guid>https://communities.sas.com/t5/New-SAS-User/deleting-observations-conditioned-by-previous-observations/m-p/672501#M23434</guid>
      <dc:creator>RTN</dc:creator>
      <dc:date>2020-07-27T12:06:17Z</dc:date>
    </item>
    <item>
      <title>Re: deleting observations conditioned by previous observations</title>
      <link>https://communities.sas.com/t5/New-SAS-User/deleting-observations-conditioned-by-previous-observations/m-p/672503#M23435</link>
      <description>&lt;P&gt;Hi&amp;nbsp;&lt;a href="https://communities.sas.com/t5/user/viewprofilepage/user-id/299137"&gt;@RTN&lt;/a&gt;&amp;nbsp; Perhaps, what genius&amp;nbsp;&lt;a href="https://communities.sas.com/t5/user/viewprofilepage/user-id/31461"&gt;@mkeintz&lt;/a&gt;&amp;nbsp;calls this "Readymeals" solution might just suffice &lt;span class="lia-unicode-emoji" title=":slightly_smiling_face:"&gt;🙂&lt;/span&gt; . So here's the lazy one-&lt;/P&gt;
&lt;PRE&gt;&lt;CODE class=" language-sas"&gt;
data have;
input ID   HA;
cards;
1     1

1     3

2     3

2     3

2     3

3     2

3     3

3     3

4     1

4     2

4     3
;
proc sql;
create table want as
select *
from have
group by id
having min(ha)=ha;
quit;&lt;/CODE&gt;&lt;/PRE&gt;
&lt;P&gt;&amp;nbsp;&amp;nbsp;&lt;/P&gt;</description>
      <pubDate>Mon, 27 Jul 2020 12:16:55 GMT</pubDate>
      <guid>https://communities.sas.com/t5/New-SAS-User/deleting-observations-conditioned-by-previous-observations/m-p/672503#M23435</guid>
      <dc:creator>novinosrin</dc:creator>
      <dc:date>2020-07-27T12:16:55Z</dc:date>
    </item>
    <item>
      <title>Re: deleting observations conditioned by previous observations</title>
      <link>https://communities.sas.com/t5/New-SAS-User/deleting-observations-conditioned-by-previous-observations/m-p/672505#M23436</link>
      <description>Are you ok with sorting the data?  Can I assume that the only possible values for HA are 1, 2, 3?</description>
      <pubDate>Mon, 27 Jul 2020 12:18:42 GMT</pubDate>
      <guid>https://communities.sas.com/t5/New-SAS-User/deleting-observations-conditioned-by-previous-observations/m-p/672505#M23436</guid>
      <dc:creator>Quentin</dc:creator>
      <dc:date>2020-07-27T12:18:42Z</dc:date>
    </item>
    <item>
      <title>Re: deleting observations conditioned by previous observations</title>
      <link>https://communities.sas.com/t5/New-SAS-User/deleting-observations-conditioned-by-previous-observations/m-p/672506#M23437</link>
      <description>&lt;BLOCKQUOTE&gt;&lt;HR /&gt;&lt;a href="https://communities.sas.com/t5/user/viewprofilepage/user-id/299137"&gt;@RTN&lt;/a&gt;&amp;nbsp;wrote:&lt;BR /&gt;When one ID has neither HA=1 nor HA=2, then I want to keep all observations.&lt;HR /&gt;&lt;/BLOCKQUOTE&gt;
&lt;P&gt;Actually, that wasn't my question.&lt;/P&gt;</description>
      <pubDate>Mon, 27 Jul 2020 12:18:54 GMT</pubDate>
      <guid>https://communities.sas.com/t5/New-SAS-User/deleting-observations-conditioned-by-previous-observations/m-p/672506#M23437</guid>
      <dc:creator>PaigeMiller</dc:creator>
      <dc:date>2020-07-27T12:18:54Z</dc:date>
    </item>
    <item>
      <title>Re: deleting observations conditioned by previous observations</title>
      <link>https://communities.sas.com/t5/New-SAS-User/deleting-observations-conditioned-by-previous-observations/m-p/672508#M23438</link>
      <description>I am ok with sorting the data and the only values for HA are 1,2 or 3.</description>
      <pubDate>Mon, 27 Jul 2020 12:22:31 GMT</pubDate>
      <guid>https://communities.sas.com/t5/New-SAS-User/deleting-observations-conditioned-by-previous-observations/m-p/672508#M23438</guid>
      <dc:creator>RTN</dc:creator>
      <dc:date>2020-07-27T12:22:31Z</dc:date>
    </item>
    <item>
      <title>Re: deleting observations conditioned by previous observations</title>
      <link>https://communities.sas.com/t5/New-SAS-User/deleting-observations-conditioned-by-previous-observations/m-p/672510#M23439</link>
      <description>&lt;P&gt;You could do it by sorting, then using first.id to pick off the first record.&amp;nbsp; If it's a 1 or 2, you output it.&amp;nbsp; If it's a 3, that means all records for that ID are 3's, and you want to output them all.&amp;nbsp;&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;P&gt;So you could do it like:&lt;/P&gt;
&lt;PRE&gt;&lt;CODE class=" language-sas"&gt;data have ;
 input ID HA ;
 cards ;
1     1
1     3
2     3
2     3
2     3
3     2
3     3
3     3
4     1
4     2
4     3
;
run ;

proc sort data=have ;
  by id ha ;
run ;

data want ;
  set have ;
  by id ;    
  retain allthrees ;
  if first.id then do ;
    if HA IN (1,2) then output ;
    allthrees=(HA=3) ;
  end ;
  if allthrees then output ;
run ;&lt;/CODE&gt;&lt;/PRE&gt;</description>
      <pubDate>Mon, 27 Jul 2020 12:26:09 GMT</pubDate>
      <guid>https://communities.sas.com/t5/New-SAS-User/deleting-observations-conditioned-by-previous-observations/m-p/672510#M23439</guid>
      <dc:creator>Quentin</dc:creator>
      <dc:date>2020-07-27T12:26:09Z</dc:date>
    </item>
    <item>
      <title>Re: deleting observations conditioned by previous observations</title>
      <link>https://communities.sas.com/t5/New-SAS-User/deleting-observations-conditioned-by-previous-observations/m-p/672514#M23440</link>
      <description>&lt;P&gt;If understood your question correctly .&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;PRE&gt;&lt;CODE class=" language-sas"&gt;data have ;
 input ID HA ;
 cards ;
1     1
1     3
2     3
2     3
2     3
3     2
3     3
3     3
4     1
4     2
4     3
;
run ;
data want;
 set have;
 by id ha;
 if first.id then n=0;
 n+first.ha;
 if n=1;
 drop n;
run;&lt;/CODE&gt;&lt;/PRE&gt;</description>
      <pubDate>Mon, 27 Jul 2020 12:47:28 GMT</pubDate>
      <guid>https://communities.sas.com/t5/New-SAS-User/deleting-observations-conditioned-by-previous-observations/m-p/672514#M23440</guid>
      <dc:creator>Ksharp</dc:creator>
      <dc:date>2020-07-27T12:47:28Z</dc:date>
    </item>
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