topic Re: How to replace a date by a missing value in New SAS User

How to replace a date by a missing value

wottma — Mon, 10 Feb 2020 18:53:23 GMT

Hi SAS-Community,

I have a date variable (informat ddmmyy10.) called hctzdate. I am trying to replace one specific date with a missing value (a '.'). In my example I would like to replace the date 03/01/2007.

How can I do that?

I tried:

data work.test1_hctz; set work.test_hctz;

if hctzdate ='03jan2007'd then hctzdate=.;

informat hctzdate ddmmyy10.;

run;

There wasn't an error in the log file, however nothing happened when I looked at the data in the viewtable. I am using SAS 9.4. Can anyone help me?

Thanks a lot in advance 🙂

Re: How to replace a date by a missing value

PaigeMiller — Mon, 10 Feb 2020 19:17:52 GMT

@wottma wrote:

Hi SAS-Community,

I have a date variable (informat ddmmyy10.) called hctzdate. I am trying to replace one specific date with a missing value (a '.'). In my example I would like to replace the date 03/01/2007.

How can I do that?

I tried:

data work.test1_hctz; set work.test_hctz;

if hctzdate ='03jan2007'd then hctzdate=.;

informat hctzdate ddmmyy10.;

run;

There wasn't an error in the log file, however nothing happened when I looked at the data in the viewtable. I am using SAS 9.4. Can anyone help me?

Thanks a lot in advance 🙂

Since we don't have your data, I'm going to guess that hctzdate is really a date/time value and not a date value. Can you show us a few UNformatted values of this variable?

Re: How to replace a date by a missing value

Reeza — Mon, 10 Feb 2020 19:58:08 GMT

In general your code looks correct so are you sure it didn't work?

You need to look at the type and format, the informat of a variable isn't particularly useful unless you're reading in the data. You should remove your INFORMAT statement or change it to a FORMAT statement. If you do have a datetime as suggested by @PaigeMiller you can use the DATEPART() function to get just the date for the comparison.

data work.test1_hctz; 

set work.test_hctz;

if hctzdate ='03JAN2007'd then hctzdate=.;

format hctzdate ddmmyy10.;

run;

@wottma wrote:

Hi SAS-Community,

I have a date variable (informat ddmmyy10.) called hctzdate. I am trying to replace one specific date with a missing value (a '.'). In my example I would like to replace the date 03/01/2007.

How can I do that?

I tried:

data work.test1_hctz; set work.test_hctz;

if hctzdate ='03jan2007'd then hctzdate=.;

informat hctzdate ddmmyy10.;

run;

There wasn't an error in the log file, however nothing happened when I looked at the data in the viewtable. I am using SAS 9.4. Can anyone help me?

Thanks a lot in advance 🙂

Re: How to replace a date by a missing value

Tom — Mon, 10 Feb 2020 20:09:43 GMT

SAS stores dates as the number of days. Perhaps your values are non-integers? The date formats will ignore the fractional part of the value.

221  data test;
222    do x=.1,.5,.6;
223      date=today()+x;
224      put x= date=comma10.1 +1 date yymmdd10. ;
225    end;
226  run;

x=0.1 date=21,955.1  2020-02-10
x=0.5 date=21,955.5  2020-02-10
x=0.6 date=21,955.6  2020-02-10