How to assign condition to variables that replaces non-missings but retains missings

NonSleeper — Wed, 29 Jul 2015 06:50:25 GMT

The original data looks like:

data have;

input Var1 Var2 Var3 Var4;

datalines;

1 0 . 0

1 1 1 2

1 . . 3

0 2 3 1

;

I want to create a data that looks like:

1 0 . 0

1 0 0 0

1 . . 0

0 2 3 1

;

The idea is if Var1 = 1 then replace all non-missing values of Var2, Var3 and Var4 to 0 and keep missing values as-is.

EDIT: Will this work?

data want; set have;

array varlist

Var 2 Var3 Var4;

do i = 1 to 4;

if Var1 = 1 and varlist(i) ne . then varlist(i) = 0;

end; drop i; run;

EDIT 2: It turns out to work. Sorry for bringing it up.

Re: How to assign condition to variables that replaces non-missings but retains missings

Patrick — Wed, 29 Jul 2015 07:31:49 GMT

What about you first mark in your previous posts which answers had been helpful and which ones correct to "close off" these threads before starting a new one?

topic How to assign condition to variables that replaces non-missings but retains missings in SAS Data Management

How to assign condition to variables that replaces non-missings but retains missings

Re: How to assign condition to variables that replaces non-missings but retains missings