topic Re: Question on a practice of SQL1:essential, p161 of course note pdf in Advanced Programming

Question on a practice of SQL1:essential, p161 of course note pdf

dxiao2017 — Sun, 28 Sep 2025 12:41:28 GMT

This actually is not a question, but I was a little bit confused and frustrated by the very different thinking and coding habits people have. The practice question is as follows:

The question asks to combine two table using left join, and there are some entries exist in one table but not in the other, and these (i.e., merchants with no transactions) are what should be in the result table.

I tried twice using left join and did not come up with the correct answer. Then I tried except and still got no correct answer. And then I tried where var not in (subquery) and it works and got the same result as the above screen capture. My code is as follows:

proc sql;
select distinct merchantname 
         label='Merchant Name',
       merchantid
         label='Merchant ID',
       type
         label='Merchant Type',
       zip
         label='Merchant Zipcode'
   from sq.merchant
   where zip=10001 and 
         merchantid not in
            (select merchantid
               from sq.transaction)
    order by 2;
quit;

Then I was thinking how does the answer using left join to create this result. The code in the answer is as follows, and it creates the correct result (as shown in last screen capture):

What makes me a little bit confuse and frustrated is: using left join in this situation. If the question did not ask to use left join, I would probably choose where var not in (subquery) first, because thinking this way is much easier for me.

And I have two questions on using left join in the above code: (1) the query does not select any column from one of the table (i.e., table b, sq.transaction), I guess this is not the common practice of using left/right/inner join? Are we suppose to select columns from all tables when using left/right/inner join? (2) where b.merchantid is null;, this part is bit difficult to understand, also I do not know how this part work, because table b (i.e., the sq.transaction table) contains and only contains merchantid that HAS transactions, also for the merchantid column, there is no missing(or null) value, so how does SAS process where b.merchantid is null;?

Anyone did this question can offer some ideas? Thanks a lot!

Re: Question on a practice of SQL1:essential, p161 of course note pdf

Tom — Mon, 29 Sep 2025 01:52:52 GMT

When you do a LEFT join it means that all observations from the LEFT table will make it into the intermediate results. And when there is an observation that did not match any observation from the RIGHT table then all of the variables contributed by the RIGHT table will have a missing value. That is why the WHERE condition works.

Personally I find your answer much easier to follow. But if you need multiple variables to perform the join then you cannot use the IN operator.

Re: Question on a practice of SQL1:essential, p161 of course note pdf

Tom — Mon, 29 Sep 2025 01:57:12 GMT

Note it is much easier to do in normal SAS instead of SQL.

data want;
  merge sq.merchant sq.transaction(in=in2);
  by merchantid;
  if not in2;
  keep merchantname merchantid type zip;
  label merchantname ='Merchant Name'
        merchantid='Merchant ID'
        type='Merchant Type'
        zip='Merchant Zipcode'
  ;
run;

Re: Question on a practice of SQL1:essential, p161 of course note pdf

dxiao2017 — Mon, 29 Sep 2025 07:14:29 GMT

Thanks a lot, Tom! So the where condition works on the intermediate results.