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GeorgeSAS
Lapis Lazuli | Level 10

Hello everyone,

 

I want to print label of dataset(not variable)

DATA XX(LABEL = "This is the label of dataset xx");
X=999;
RUN;

PROC PRINT DATA=XX/LABEL;
RUN;


ERROR 200-322: The symbol is not recognized and will be ignored

 

Please help.

 

Thank you!

1 ACCEPTED SOLUTION

Accepted Solutions
ballardw
Super User

@GeorgeSAS wrote:

Hello everyone,

 

I want to print label of dataset(not variable)

DATA XX(LABEL = "This is the label of dataset xx");
X=999;
RUN;

PROC PRINT DATA=XX/LABEL;
RUN;


ERROR 200-322: The symbol is not recognized and will be ignored

 

Please help.

 

Thank you!


Sounds like you want a TITLE statement. If you want to do this automagically you would have to read the table properties, place the label into a macro variable and use that variable in a title statement.

 

data work.junk (label='This is a dataset label');
x=1;
run;

proc sql noprint;
   select memlabel into : labelvar
   from dictionary.tables
   where libname='WORK' and memname='JUNK'
   ;
run;

proc print data=work.junk ;
   title "&labelvar.";
run; title;

View solution in original post

1 REPLY 1
ballardw
Super User

@GeorgeSAS wrote:

Hello everyone,

 

I want to print label of dataset(not variable)

DATA XX(LABEL = "This is the label of dataset xx");
X=999;
RUN;

PROC PRINT DATA=XX/LABEL;
RUN;


ERROR 200-322: The symbol is not recognized and will be ignored

 

Please help.

 

Thank you!


Sounds like you want a TITLE statement. If you want to do this automagically you would have to read the table properties, place the label into a macro variable and use that variable in a title statement.

 

data work.junk (label='This is a dataset label');
x=1;
run;

proc sql noprint;
   select memlabel into : labelvar
   from dictionary.tables
   where libname='WORK' and memname='JUNK'
   ;
run;

proc print data=work.junk ;
   title "&labelvar.";
run; title;

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