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lillymaginta
Lapis Lazuli | Level 10
data a;
  input patientid  start1_date : mmddyy10. end1_date : mmddyy10. start2 : mmddyy10.  end2 : mmddyy10. ;
  format  start1_date end1_date start2 end2  mmddyy10.;
datalines;
1 5/5/2009 6/6/2009  1/1/2006 2/2/2006
1 5/5/2009 6/6/2009  2/2/2007 3/2/2007
1 5/5/2009 6/6/2009 5/1/2009 6/1/2009
1 5/5/2009 6/6/2009 7/7/2009 12/1/2009;
run;

I have the above data. I am trying to create a subset that includes all periods for (start2-end2) that overlap with any of the intervals from (start1_date- end1_date). No requirement for a minimum overlap in days. 

Required output for this data

1 5/5/2009 6/6/2009 5/1/2009 6/1/2009

 

1 ACCEPTED SOLUTION

Accepted Solutions
mansour_ib_sas
Pyrite | Level 9

Hello,

I propose this solution:

data a;
  input patientid  start1_date : mmddyy10. end1_date : mmddyy10. start2 : mmddyy10.  end2 : mmddyy10. ;
  format  start1_date end1_date start2 end2  mmddyy10.;
datalines;
1 5/5/2009 6/6/2009  1/1/2006 2/2/2006
1 5/5/2009 6/6/2009  2/2/2007 3/2/2007
1 5/5/2009 6/6/2009 5/1/2009 6/1/2009
1 5/5/2009 6/6/2009 7/7/2009 12/1/2009
;
run;

data b;
do until (last.patientid);
set a;
by patientid;
if intnx('month',start1_date,0,"BEGINNING")=intnx('month',start2,0,"BEGINNING")
and 
intnx('month',end1_date,0,"BEGINNING")=intnx('month',end2,0,"BEGINNING")
then output;
end;

run;

View solution in original post

3 REPLIES 3
novinosrin
Tourmaline | Level 20

Hi @lillymaginta  While I always enjoyed attempting to solve your questions, this one is not quite clear. I m wary of my understanding of the requirement.

Anyways:

 

data a;
  input patientid  start1_date : mmddyy10. end1_date : mmddyy10. start2 : mmddyy10.  end2 : mmddyy10. ;
  format  start1_date end1_date start2 end2  mmddyy10.;
datalines;
1 5/5/2009 6/6/2009  1/1/2006 2/2/2006
1 5/5/2009 6/6/2009  2/2/2007 3/2/2007
1 5/5/2009 6/6/2009 5/1/2009 6/1/2009
1 5/5/2009 6/6/2009 7/7/2009 12/1/2009
;
run;

proc sql;
create table want(drop=x:) as
select *,abs (start2-start1_date) as x1,abs(end2-end1_date) as x2
from a
group by patientid
having min(abs (start2-start1_date))=x1 and min(abs(end2-end1_date))=x2
order by patientid,start2,end2;
quit;
mansour_ib_sas
Pyrite | Level 9

Hello,

I propose this solution:

data a;
  input patientid  start1_date : mmddyy10. end1_date : mmddyy10. start2 : mmddyy10.  end2 : mmddyy10. ;
  format  start1_date end1_date start2 end2  mmddyy10.;
datalines;
1 5/5/2009 6/6/2009  1/1/2006 2/2/2006
1 5/5/2009 6/6/2009  2/2/2007 3/2/2007
1 5/5/2009 6/6/2009 5/1/2009 6/1/2009
1 5/5/2009 6/6/2009 7/7/2009 12/1/2009
;
run;

data b;
do until (last.patientid);
set a;
by patientid;
if intnx('month',start1_date,0,"BEGINNING")=intnx('month',start2,0,"BEGINNING")
and 
intnx('month',end1_date,0,"BEGINNING")=intnx('month',end2,0,"BEGINNING")
then output;
end;

run;
lillymaginta
Lapis Lazuli | Level 10

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