BookmarkSubscribeRSS Feed
🔒 This topic is solved and locked. Need further help from the community? Please sign in and ask a new question.
bkq32
Quartz | Level 8

I have a variable that has a first name and last name embedded in it. How can I extract the name into a new variable, assuming it always comes after "Requestor: " and before "Reason:"?

 

data have; 
 length note $200.;
 input note $ ;
cards;
This_is_the_Requestor:_Mary_L._Santiago_Reason:
Additional_text_This_is_the_Requestor:_John_Doe_Reason:_stuff
This_is_the_Requestor:_Tyler_Nguyen_Reason:_text_text
;
run;

data have;
 set have;
 note = tranwrd ( note, "_", " " );
run;
1 ACCEPTED SOLUTION

Accepted Solutions
Shmuel
Garnet | Level 18

Sorry, it seems that I had some misunderstanding;

 

try next code:

data have; 
 length note $200.;
 input note $ ;
 note = tranwrd ( note, "_", " " );
cards;
This_is_the_Requestor:_Mary_L._Santiago_Reason:
Additional_text_This_is_the_Requestor:_John_Doe_Reason:_stuff
This_is_the_Requestor:_Tyler_Nguyen_Reason:_text_text
;
run;

data want;
 set have;
     pos1 = findw(note,"Requestor:");
     pos2 = findw(note,"Reason:");
     fullname = strip(substr(note,pos1+10,pos2-pos1-10));
drop pos1 pos2; run;

View solution in original post

4 REPLIES 4
Shmuel
Garnet | Level 18

The delimiter between the two names id ":" then:

first_name = scan(note,1,":");
second_name = scan(note,2,":");
Shmuel
Garnet | Level 18

Sorry, it seems that I had some misunderstanding;

 

try next code:

data have; 
 length note $200.;
 input note $ ;
 note = tranwrd ( note, "_", " " );
cards;
This_is_the_Requestor:_Mary_L._Santiago_Reason:
Additional_text_This_is_the_Requestor:_John_Doe_Reason:_stuff
This_is_the_Requestor:_Tyler_Nguyen_Reason:_text_text
;
run;

data want;
 set have;
     pos1 = findw(note,"Requestor:");
     pos2 = findw(note,"Reason:");
     fullname = strip(substr(note,pos1+10,pos2-pos1-10));
drop pos1 pos2; run;
andreas_lds
Jade | Level 19

As soon as personal names are involved, sooner or later things will get interesting. Without a proper delimiter between first-name and last-name this problem can't be solved, because the number of words forming first-name and last-name is rarely two (one word for each), starting the interesting part: from the second to the next-to-last word you have to decide, whether the word belongs to first-name or last-name. This is pure guesswork and will not lead to usable results.

 

The following step extracts the names and stores in in one variable:

data want;
   set have;
   
   length FullName $ 40 rxName 8;
   retain rxName;
   drop rxName;
   
   if _n_ = 1 then do;
      rxName = prxparse('/requestor:_(.+)_reason/i');
   end;
   
   if prxmatch(rxName, note) then do;
      FullName = prxposn(rxName, 1, note);
      FullName = translate(FullName, ' ', '_');
   end;
run;
Kurt_Bremser
Super User

Try this:

data want;
set have;
length name $30;
note = scan(note,2,':');
call scan(note,-1,pos,le,'_','m');
name = translate(substr(note,2,pos - 2),' ','_');
keep name;
run;

sas-innovate-2024.png

Available on demand!

Missed SAS Innovate Las Vegas? Watch all the action for free! View the keynotes, general sessions and 22 breakouts on demand.

 

Register now!

Mastering the WHERE Clause in PROC SQL

SAS' Charu Shankar shares her PROC SQL expertise by showing you how to master the WHERE clause using real winter weather data.

Find more tutorials on the SAS Users YouTube channel.

Discussion stats
  • 4 replies
  • 1457 views
  • 6 likes
  • 4 in conversation